19.09.2019 Views

fluid_mechanics

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

582 Chapter 11 ■ Compressible Flow<br />

Differentiating Eq. 11.10 leads to<br />

or<br />

dȟ dǔ R dT<br />

dȟ<br />

dT dǔ<br />

dT R<br />

From Eqs. 11.3, 11.7, and 11.11 we conclude that<br />

c p c v R<br />

(11.11)<br />

(11.12)<br />

Equation 11.12 indicates that the difference between c p and c v is constant for each ideal gas regardless<br />

of temperature. Also c p 7 c v . If the specific heat ratio, k, is defined as<br />

then combining Eqs. 11.12 and 11.13 leads to<br />

c p <br />

k c p<br />

c v<br />

Rk<br />

k 1<br />

(11.13)<br />

(11.14)<br />

and<br />

c v <br />

R<br />

k 1<br />

(11.15)<br />

The gas constant is<br />

related to the specific<br />

heat values.<br />

Actually, c p , c v , and k are all somewhat temperature dependent for any ideal gas. We will assume<br />

constant values for these variables in this book. Values of k and R for some commonly used gases at<br />

nominal temperatures are listed in Tables 1.7 and 1.8. These tabulated values can be used with Eqs.<br />

11.13 and 11.14 to determine the values of c p and c v . Example 11.1 demonstrates how internal energy<br />

and enthalpy changes can be calculated for a flowing ideal gas having constant and c v .<br />

c p<br />

E XAMPLE 11.1<br />

Internal Energy, Enthalpy, and Density for an Ideal Gas<br />

GIVEN Air flows steadily between two sections in a long<br />

straight portion of 4-in.-diameter pipe as is indicated in Fig. E11.1.<br />

The uniformly distributed temperature and pressure at each section<br />

are T 1 540 °R, p 1 100 psia, and T 2 453 °R, p 2 18.4 psia.<br />

Flow<br />

Pipe Control volume<br />

Section (1) Section (2)<br />

D 1 = D 2 = 4 in.<br />

D<br />

SOLUTION<br />

(a) Assuming air behaves as an ideal gas, we can use Eq. 11.5 to<br />

evaluate the change in internal energy between sections 112 and 122.<br />

Thus<br />

ǔ 2 ǔ 1 c v 1T 2 T 1 2<br />

(1)<br />

From Eq. 11.15 we have<br />

c v <br />

R<br />

k 1<br />

and from Table 1.7, R 1716 1ft # lb21slug # °R2 and k 1.4.<br />

Throughout this book, we use the nominal values of k for<br />

common gases listed in Tables 1.7 and 1.8 and consider these values<br />

as being representative. Since English Engineering System<br />

(2)<br />

units are used more often than British Gravitational System units<br />

in compressible flow discussions, we use<br />

to get<br />

F I G U R E E11.1<br />

FIND Calculate the 1a2 change in internal energy between sections<br />

112 and 122, 1b2 change in enthalpy between sections 112 and<br />

122, and 1c2 change in density between sections 112 and 122.<br />

1 slug 32 .174 lbm<br />

R 1716 1ft # lb21slug # °R2<br />

32.174 1lbmslug2<br />

53.3 1ft # lb21lbm # °R2

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!