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10.3 Energy Considerations 545<br />

COMMENT If the flow conditions upstream of the ramp<br />

were supercritical, the free-surface elevation and <strong>fluid</strong> depth<br />

would increase as the <strong>fluid</strong> flows up the ramp. This is indicated in<br />

Fig. E10.2c along with the corresponding specific energy diagram,<br />

as is shown in Fig. E10.2d. For this case the flow starts at<br />

112 on the lower 1supercritical2 branch of the specific energy curve<br />

and ends at 122 on the same branch with y 2 7 y 1 . Since both y and<br />

z increase from 112 to 122, the surface elevation, y z, also<br />

increases. Thus, flow up a ramp is different for subcritical than it<br />

is for supercritical conditions.<br />

y<br />

V 2 > c 2<br />

y 2 > y 1<br />

y<br />

V 1 > c 1<br />

1 0.5 ft<br />

y 2<br />

y 1<br />

(2)<br />

0.5 ft<br />

(1)<br />

E<br />

(c)<br />

F I G U R E E10.2<br />

(Continued)<br />

(d)<br />

10.3.2 Channel Depth Variations<br />

By using the concepts of the specific energy and critical flow conditions 1Fr 12, it is possible to<br />

determine how the depth of a flow in an open channel changes with distance along the channel.<br />

In some situations the depth change is very rapid so that the value of dydx is of the order of 1.<br />

Complex effects involving two- or three-dimensional flow phenomena are often involved in such<br />

flows.<br />

In this section we consider only gradually varying flows. For such flows, dydx 1 and it<br />

is reasonable to impose the one-dimensional velocity assumption. At any section the total head is<br />

H V 2 2g y z and the energy equation 1Eq. 10.52 becomes<br />

H 1 H 2 h L<br />

where h L is the head loss between sections 112 and 122.<br />

As is discussed in the previous section, the slope of the energy line is dHdx dh L dx S f and<br />

the slope of the channel bottom is dzdx S 0 . Thus, since<br />

we obtain<br />

or<br />

dH<br />

dx d dx aV2 2g y zb V dV<br />

g dx dy<br />

dx dz<br />

dx<br />

dh L<br />

dx V dV<br />

g dx dy<br />

dx S 0<br />

V dV<br />

g dx dy<br />

dx S f S 0<br />

For a given flowrate per unit width, q, in a rectangular channel of constant width b, we have<br />

or by differentiation<br />

dV<br />

dx q dy<br />

y 2 dx V dy<br />

y dx<br />

(10.12)<br />

V qy

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