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490 Chapter 9 ■ Flow over Immersed Bodies<br />

The pressure gradient<br />

in the external<br />

flow is imposed<br />

throughout the<br />

boundary layer<br />

<strong>fluid</strong>.<br />

Separation<br />

location<br />

V9.6 Snow drifts<br />

object in an inviscid <strong>fluid</strong> is zero, but the drag on an object in a <strong>fluid</strong> with vanishingly small 1but<br />

nonzero2 viscosity is not zero.<br />

The reason for the above paradox can be described in terms of the effect of the pressure<br />

gradient on boundary layer flow. Consider large Reynolds number flow of a real 1viscous2 <strong>fluid</strong><br />

past a circular cylinder. As was discussed in Section 9.1.2, we expect the viscous effects to be<br />

confined to thin boundary layers near the surface. This allows the <strong>fluid</strong> to stick 1V 02 to the<br />

surface—a necessary condition for any <strong>fluid</strong>, provided m 0. The basic idea of boundary layer<br />

theory is that the boundary layer is thin enough so that it does not greatly disturb the flow outside<br />

the boundary layer. Based on this reasoning, for large Reynolds numbers the flow throughout<br />

most of the flow field would be expected to be as is indicated in Fig. 9.16a, the inviscid<br />

flow field.<br />

The pressure distribution indicated in Fig. 9.16b is imposed on the boundary layer flow along<br />

the surface of the cylinder. In fact, there is negligible pressure variation across the thin boundary<br />

layer so that the pressure within the boundary layer is that given by the inviscid flow field. This<br />

pressure distribution along the cylinder is such that the stationary <strong>fluid</strong> at the nose of the cylinder<br />

1U fs 0 at u 02 is accelerated to its maximum velocity 1U fs 2U at u 90°2 and then is decelerated<br />

back to zero velocity at the rear of the cylinder 1U fs 0 at u 180°2. This is accomplished<br />

by a balance between pressure and inertia effects; viscous effects are absent for the inviscid<br />

flow outside the boundary layer.<br />

Physically, in the absence of viscous effects, a <strong>fluid</strong> particle traveling from the front to<br />

the back of the cylinder coasts down the “pressure hill” from u 0 to u 90° 1from point A<br />

to C in Fig. 9.16b2 and then back up the hill to u 180° 1from point C to F2 without any loss<br />

of energy. There is an exchange between kinetic and pressure energy, but there are no energy<br />

losses. The same pressure distribution is imposed on the viscous <strong>fluid</strong> within the boundary layer.<br />

The decrease in pressure in the direction of flow along the front half of the cylinder is termed<br />

a favorable pressure gradient. The increase in pressure in the direction of flow along the rear<br />

half of the cylinder is termed an adverse pressure gradient.<br />

Consider a <strong>fluid</strong> particle within the boundary layer indicated in Fig. 9.17a. In its attempt<br />

to flow from A to F it experiences the same pressure distribution as the particles in the free<br />

stream immediately outside the boundary layer—the inviscid flow field pressure. However,<br />

because of the viscous effects involved, the particle in the boundary layer experiences a loss<br />

of energy as it flows along. This loss means that the particle does not have enough energy to<br />

coast all of the way up the pressure hill 1from C to F2 and to reach point F at the rear of the<br />

cylinder. This kinetic energy deficit is seen in the velocity profile detail at point C, shown in<br />

Fig. 9.17a. Because of friction, the boundary layer <strong>fluid</strong> cannot travel from the front to the<br />

rear of the cylinder. 1This conclusion can also be obtained from the concept that due to viscous<br />

effects the particle at C does not have enough momentum to allow it to coast up the pressure<br />

hill to F.2<br />

The situation is similar to a bicyclist coasting down a hill and up the other side of the valley.<br />

If there were no friction, the rider starting with zero speed could reach the same height from<br />

which he or she started. Clearly friction 1rolling resistance, aerodynamic drag, etc.2 causes a loss<br />

of energy 1and momentum2, making it impossible for the rider to reach the height from which he<br />

or she started without supplying additional energy 1i.e., pedaling2. The <strong>fluid</strong> within the boundary<br />

layer does not have such an energy supply. Thus, the <strong>fluid</strong> flows against the increasing pressure as<br />

far as it can, at which point the boundary layer separates from 1lifts off2 the surface. This boundary<br />

layer separation is indicated in Fig. 9.17a as well as the figures in the margin. (See the photograph<br />

at the beginning of Chapters 7, 9, and 11.) Typical velocity profiles at representative locations<br />

along the surface are shown in Fig. 9.17b. At the separation location 1profile D2, the velocity<br />

gradient at the wall and the wall shear stress are zero. Beyond that location 1from D to E2 there is<br />

reverse flow in the boundary layer.<br />

As is indicated in Fig. 9.17c, because of the boundary layer separation, the average pressure<br />

on the rear half of the cylinder is considerably less than that on the front half. Thus, a large pressure<br />

drag is developed, even though 1because of small viscosity2 the viscous shear drag may be<br />

quite small. D’Alembert’s paradox is explained. No matter how small the viscosity, provided it is<br />

not zero, there will be a boundary layer that separates from the surface, giving a drag that is, for<br />

the most part, independent of the value of m.

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