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488 Chapter 9 ■ Flow over Immersed Bodies E XAMPLE 9.7 Drag on a Flat Plate GIVEN The water ski shown in Fig. E9.7a moves through 70 °F water with a velocity U. FIND Estimate the drag caused by the shear stress on the bottom of the ski for 0 6 U 6 30 fts. SOLUTION Clearly the ski is not a flat plate, and it is not aligned exactly parallel to the upstream flow. However, we can obtain a reasonable approximation to the shear force by using the flat plate results. That is, the friction drag, d f , caused by the shear stress on the bottom of the ski 1the wall shear stress2 can be determined as With A /b 4 ft 0.5 ft 2 ft 2 , r 1.94 slugsft 3 , and m 2.04 10 5 lb # sft 2 1see Table B.12 we obtain where d f and U are in pounds and fts, respectively. The friction coefficient, C Df , can be obtained from Fig. 9.15 or from the appropriate equations given in Table 9.3. As we will see, for this problem, much of the flow lies within the transition regime where both the laminar and turbulent portions of the boundary layer flow occupy comparable lengths of the plate. We choose to use the values of C Df from the table. For the given conditions we obtain Re / rU/ m d f 1 2 rU 2 /bC Df d f 1 211.94 slugsft 3 212.0 ft 2 2U 2 C Df 1.94 U 2 C Df 11.94 slugs ft 3 214 ft2U 2.04 10 5 lb # sft 2 3.80 105 U where U is in fts. With U 10 fts, or Re / 3.80 10 6 , we obtain from Table 9.3 C Df 0.4551log Re / 2 2.58 1700Re / (1) 0.00308. From Eq. 1 the corresponding drag is d f 1.941102 2 10.003082 0.598 lb By covering the range of upstream velocities of interest we obtain the results shown in Fig. E9.7b. (Ans) COMMENTS If Re f 1000, the results of boundary layer theory are not valid—inertia effects are not dominant enough and the boundary layer is not thin compared with the length of the plate. For our problem this corresponds to U 2.63 10 3 fts. For all practical purposes U is greater than this value, and the flow past the ski is of the boundary layer type. The approximate location of the transition from laminar to turbulent boundary layer flow as defined by Re cr rUx crm 5 10 5 is indicated in Fig. E9.7b. Up to U 1.31 fts the entire boundary layer is laminar. The fraction of the boundary layer that is laminar decreases as U increases until only the front 0.18 ft is laminar when U 30 fts. For anyone who has water skied, it is clear that it can require considerably more force to be pulled along at 30 fts than the 2 4.88 lb 9.76 lb 1two skis2 indicated in Fig. E9.7b. As is discussed in Section 9.3, the total drag on an object such as a water ski consists of more than just the friction drag. Other components, including pressure drag and wave-making drag, add considerably to the total resistance. 5 4 Entire boundary layer laminar 5 4 U x = 0 x b = width = 0.5 ft x = 4 ft = f , lb 3 2 x cr f 3 2 x cr , ft (a) 1 1 F I G U R E E9.7 0 0 5 10 15 20 25 30 U, ft/s (b) 9.2.6 Effects of Pressure Gradient The boundary layer discussions in the previous parts of Section 9.2 have dealt with flow along a flat plate in which the pressure is constant throughout the fluid. In general, when a fluid flows past an object other than a flat plate, the pressure field is not uniform. As shown in Fig. 9.6, if the Reynolds number is large, relatively thin boundary layers will develop along the surfaces. Within

9.2 Boundary Layer Characteristics 489 U fs1 U fs2 p 1 p 2 The free-stream velocity on a curved surface is not constant. U (1) U fs = U U fs = 0 (2) U fs = 2U these layers the component of the pressure gradient in the streamwise direction 1i.e., along the body surface2 is not zero, although the pressure gradient normal to the surface is negligibly small. That is, if we were to measure the pressure while moving across the boundary layer from the body to the boundary layer edge, we would find that the pressure is essentially constant. However, the pressure does vary in the direction along the body surface if the body is curved, as shown by the figure in the margin. The variation in the free-stream velocity, U fs , the fluid velocity at the edge of the boundary layer, is the cause of the pressure gradient in this direction. The characteristics of the entire flow 1both within and outside of the boundary layer2 are often highly dependent on the pressure gradient effects on the fluid within the boundary layer. For a flat plate parallel to the upstream flow, the upstream velocity 1that far ahead of the plate2 and the free-stream velocity 1that at the edge of the boundary layer2 are equal— U U fs . This is a consequence of the negligible thickness of the plate. For bodies of nonzero thickness, these two velocities are different. This can be seen in the flow past a circular cylinder of diameter D. The upstream velocity and pressure are U and p 0 , respectively. If the fluid were completely inviscid 1m 02, the Reynolds number would be infinite 1Re rUDm 2 and the streamlines would be symmetrical, as are shown in Fig. 9.16a. The fluid velocity along the surface would vary from U fs 0 at the very front and rear of the cylinder 1points A and F are stagnation points2 to a maximum of U fs 2U at the top and bottom of the cylinder 1point C2. This is also indicated in the figure in the margin. The pressure on the surface of the cylinder would be symmetrical about the vertical midplane of the cylinder, reaching a maximum value of p 0 rU 2 2 1the stagnation pressure2 at both the front and back of the cylinder, and a minimum of p 0 3rU 2 2 at the top and bottom of the cylinder. The pressure and free-stream velocity distributions are shown in Figs. 9.16b and 9.16c. These characteristics can be obtained from potential flow analysis of Section 6.6.3. Because of the absence of viscosity 1therefore, t w 02 and the symmetry of the pressure distribution for inviscid flow past a circular cylinder, it is clear that the drag on the cylinder is zero. Although it is not obvious, it can be shown that the drag is zero for any object that does not produce a lift 1symmetrical or not2 in an inviscid fluid 1Ref. 42. Based on experimental evidence, however, we know that there must be a net drag. Clearly, since there is no purely inviscid fluid, the reason for the observed drag must lie on the shoulders of the viscous effects. To test this hypothesis, we could conduct an experiment by measuring the drag on an object 1such as a circular cylinder2 in a series of fluids with decreasing values of viscosity. To our initial surprise we would find that no matter how small we make the viscosity 1provided it is not precisely zero2 we would measure a finite drag, essentially independent of the value of m. As was noted in Section 6.6.3, this leads to what has been termed d’Alembert’s paradox—the drag on an U fs C A θ F (a) U, p 0 A 1 p 0 + ρU 2 2 p 0 F 2U C p 1 p 0 – ρU 2 2 p 0 – ρU 2 U fs U 3 p 0 – ρU 2 2 C 0 90 180 θ , degrees (b) A F 0 0 90 180 θ , degrees (c) F I G U R E 9.16 Inviscid flow past a circular cylinder: (a) streamlines for the flow if there were no viscous effects, (b) pressure distribution on the cylinder’s surface, (c) free-stream velocity on the cylinder’s surface.

9.2 Boundary Layer Characteristics 489<br />

U fs1 U fs2<br />

p 1 p 2<br />

The free-stream velocity<br />

on a curved<br />

surface is not<br />

constant.<br />

U<br />

(1)<br />

U fs = U<br />

U fs = 0<br />

(2)<br />

U fs = 2U<br />

these layers the component of the pressure gradient in the streamwise direction 1i.e., along the body<br />

surface2 is not zero, although the pressure gradient normal to the surface is negligibly small. That<br />

is, if we were to measure the pressure while moving across the boundary layer from the body to<br />

the boundary layer edge, we would find that the pressure is essentially constant. However, the pressure<br />

does vary in the direction along the body surface if the body is curved, as shown by the figure<br />

in the margin. The variation in the free-stream velocity, U fs , the <strong>fluid</strong> velocity at the edge of<br />

the boundary layer, is the cause of the pressure gradient in this direction. The characteristics of the<br />

entire flow 1both within and outside of the boundary layer2 are often highly dependent on the pressure<br />

gradient effects on the <strong>fluid</strong> within the boundary layer.<br />

For a flat plate parallel to the upstream flow, the upstream velocity 1that far ahead of the<br />

plate2 and the free-stream velocity 1that at the edge of the boundary layer2 are equal— U U fs .<br />

This is a consequence of the negligible thickness of the plate. For bodies of nonzero thickness,<br />

these two velocities are different. This can be seen in the flow past a circular cylinder of diameter<br />

D. The upstream velocity and pressure are U and p 0 , respectively. If the <strong>fluid</strong> were completely<br />

inviscid 1m 02, the Reynolds number would be infinite 1Re rUDm 2 and the streamlines<br />

would be symmetrical, as are shown in Fig. 9.16a. The <strong>fluid</strong> velocity along the surface would<br />

vary from U fs 0 at the very front and rear of the cylinder 1points A and F are stagnation points2<br />

to a maximum of U fs 2U at the top and bottom of the cylinder 1point C2. This is also indicated<br />

in the figure in the margin. The pressure on the surface of the cylinder would be symmetrical<br />

about the vertical midplane of the cylinder, reaching a maximum value of p 0 rU 2 2 1the stagnation<br />

pressure2 at both the front and back of the cylinder, and a minimum of p 0 3rU 2 2 at the<br />

top and bottom of the cylinder. The pressure and free-stream velocity distributions are shown in<br />

Figs. 9.16b and 9.16c. These characteristics can be obtained from potential flow analysis of Section<br />

6.6.3.<br />

Because of the absence of viscosity 1therefore, t w 02 and the symmetry of the pressure<br />

distribution for inviscid flow past a circular cylinder, it is clear that the drag on the cylinder is zero.<br />

Although it is not obvious, it can be shown that the drag is zero for any object that does not produce<br />

a lift 1symmetrical or not2 in an inviscid <strong>fluid</strong> 1Ref. 42. Based on experimental evidence, however, we<br />

know that there must be a net drag. Clearly, since there is no purely inviscid <strong>fluid</strong>, the reason for the<br />

observed drag must lie on the shoulders of the viscous effects.<br />

To test this hypothesis, we could conduct an experiment by measuring the drag on an object<br />

1such as a circular cylinder2 in a series of <strong>fluid</strong>s with decreasing values of viscosity. To our initial<br />

surprise we would find that no matter how small we make the viscosity 1provided it is not precisely<br />

zero2 we would measure a finite drag, essentially independent of the value of m. As was<br />

noted in Section 6.6.3, this leads to what has been termed d’Alembert’s paradox—the drag on an<br />

U fs<br />

C<br />

A<br />

θ<br />

F<br />

(a)<br />

U, p 0<br />

A<br />

1<br />

p 0 + ρU 2<br />

2<br />

p 0<br />

F<br />

2U<br />

C<br />

p<br />

1<br />

p 0 – ρU 2<br />

2<br />

p 0 – ρU 2<br />

U fs<br />

U<br />

3<br />

p 0 – ρU 2<br />

2<br />

C<br />

0 90 180<br />

θ , degrees<br />

(b)<br />

A<br />

F<br />

0<br />

0 90 180<br />

θ , degrees<br />

(c)<br />

F I G U R E 9.16 Inviscid flow past a<br />

circular cylinder: (a) streamlines for the flow if<br />

there were no viscous effects, (b) pressure distribution<br />

on the cylinder’s surface, (c) free-stream velocity<br />

on the cylinder’s surface.

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