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7.7 Correlation of Experimental Data 351<br />

the measurements?2. The simplest problems are obviously those involving the fewest pi terms,<br />

and the following sections indicate how the complexity of the analysis increases with the increasing<br />

number of pi terms.<br />

If only one pi term<br />

is involved in a<br />

problem, it must be<br />

equal to a constant.<br />

7.7.1 Problems with One Pi Term<br />

Application of the pi theorem indicates that if the number of variables minus the number of reference<br />

dimensions is equal to unity, then only one pi term is required to describe the phenomenon.<br />

The functional relationship that must exist for one pi term is<br />

ß 1 C<br />

where C is a constant. This is one situation in which a dimensional analysis reveals the specific<br />

form of the relationship and, as is illustrated by the following example, shows how the individual<br />

variables are related. The value of the constant, however, must still be determined by experiment.<br />

E XAMPLE 7.3<br />

Flow with Only One Pi Term<br />

GIVEN As shown in Fig. E7.3, assume that the drag, d, acting<br />

on a spherical particle that falls very slowly through a viscous<br />

<strong>fluid</strong>, is a function of the particle diameter, D, the particle<br />

velocity, V, and the <strong>fluid</strong> viscosity, .<br />

FIND Determine, with the aid of dimensional analysis, how<br />

the drag depends on the particle velocity.<br />

D<br />

= f(D,V, μ )<br />

V7.7 Stokes flow<br />

SOLUTION<br />

From the information given, it follows that<br />

d f(D, V, )<br />

and the dimensions of the variables are<br />

We see that there are four variables and three reference dimensions<br />

(F, L, and T) required to describe the variables. Thus, according<br />

to the pi theorem, one pi term is required. This pi term<br />

can be easily formed by inspection and can be expressed as<br />

Because there is only one pi term, it follows that<br />

where C is a constant. Thus,<br />

d F<br />

D L<br />

V LT 1<br />

FL 2 T<br />

ß 1 <br />

d<br />

VD<br />

d<br />

VD C<br />

d CVD<br />

Thus, for a given particle and <strong>fluid</strong>, the drag varies directly with<br />

the velocity so that<br />

d r V<br />

(Ans)<br />

V<br />

μ<br />

F I G U R E E7.3<br />

COMMENTS Actually, the dimensional analysis reveals that<br />

the drag not only varies directly with the velocity, but it also<br />

varies directly with the particle diameter and the <strong>fluid</strong> viscosity.<br />

We could not, however, predict the value of the drag, since the<br />

constant, C, is unknown. An experiment would have to be performed<br />

in which the drag and the corresponding velocity are measured<br />

for a given particle and <strong>fluid</strong>. Although in principle we<br />

would only have to run a single test, we would certainly want to<br />

repeat it several times to obtain a reliable value for C. It should be<br />

emphasized that once the value of C is determined it is not necessary<br />

to run similar tests by using different spherical particles and<br />

<strong>fluid</strong>s; that is, C is a universal constant so long as the drag is a<br />

function only of particle diameter, velocity, and <strong>fluid</strong> viscosity.<br />

An approximate solution to this problem can also be obtained<br />

theoretically, from which it is found that C 3 so that<br />

d 3VD<br />

This equation is commonly called Stokes law and is used in the<br />

study of the settling of particles. Our experiments would reveal that<br />

this result is only valid for small Reynolds numbers (VD/ 1).<br />

This follows, since in the original list of variables, we have

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