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302 Chapter 6 ■ Differential Analysis of Fluid Flow<br />

y<br />

dθ<br />

p s<br />

F y<br />

a<br />

F x<br />

θ<br />

x<br />

F I G U R E 6.28<br />

on a circular cylinder.<br />

The notation for determining lift and drag<br />

V6.9 Potential and<br />

viscous flow<br />

Potential theory incorrectly<br />

predicts<br />

that the drag on a<br />

cylinder is zero.<br />

and<br />

F x<br />

2p<br />

F y p s sin u a du<br />

0<br />

(6.118)<br />

where is the drag 1force parallel to direction of the uniform flow2 and is the lift 1force perpendicular<br />

to the direction of the uniform flow2. Substitution for p s from Eq. 6.116 into these two equations, and<br />

subsequent integration, reveals that F x 0 and F y 0 1Problem 6.732. These results indicate that both<br />

the drag and lift as predicted by potential theory for a fixed cylinder in a uniform stream are zero.<br />

Since the pressure distribution is symmetrical around the cylinder, this is not really a surprising result.<br />

However, we know from experience that there is a significant drag developed on a cylinder when it is<br />

placed in a moving <strong>fluid</strong>. This discrepancy is known as d’Alembert’s paradox. The paradox is named<br />

after Jean le Rond d’Alembert 11717–17832, a French mathematician and philosopher, who first showed<br />

that the drag on bodies immersed in inviscid <strong>fluid</strong>s is zero. It was not until the latter part of the nineteenth<br />

century and the early part of the twentieth century that the role viscosity plays in the steady <strong>fluid</strong><br />

motion was understood and d’Alembert’s paradox explained 1see Section 9.12.<br />

F y<br />

E XAMPLE 6.8<br />

Potential Flow—Cylinder<br />

GIVEN When a circular cylinder is placed in a uniform<br />

stream, a stagnation point is created on the cylinder as is shown in<br />

Fig. E6.8a. If a small hole is located at this point, the stagnation<br />

pressure, p stag , can be measured and used to determine the approach<br />

velocity, U.<br />

FIND<br />

(a) Show how p stag and U are related.<br />

(b) If the cylinder is misaligned by an angle (Figure E6.8b),<br />

but the measured pressure is still interpreted as the stagnation<br />

pressure, determine an expression for the ratio of the true<br />

velocity, U, to the predicted velocity, U. Plot this ratio as a function<br />

of for the range 20 20.<br />

U<br />

U<br />

U<br />

p 0<br />

y<br />

a<br />

r<br />

θ<br />

x<br />

α<br />

a<br />

β<br />

β<br />

Stagnation<br />

point<br />

(a)<br />

(b)<br />

(d)<br />

U__<br />

U'<br />

1.5<br />

1.4<br />

1.3<br />

1.2<br />

1.1<br />

1.0<br />

–20° –10° 0° 10° 20°<br />

α<br />

(c)<br />

F I G U R E E6.8

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