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280 Chapter 6 ■ Differential Analysis of Fluid Flow<br />

ds<br />

Streamline<br />

z<br />

x<br />

y<br />

F I G U R E 6.12 The notation for<br />

differential length along a streamline.<br />

x<br />

z<br />

g<br />

g gz<br />

^ ^ ^<br />

0i 0j gk<br />

V ( V)<br />

Δ<br />

Δ<br />

V<br />

V<br />

Euler’s equations<br />

can be arranged to<br />

give the relationship<br />

among pressure,<br />

velocity, and<br />

elevation for inviscid<br />

<strong>fluid</strong>s<br />

y<br />

equation, starting from Euler’s equations. Of course, we should obtain the same result since Euler’s<br />

equations simply represent a statement of Newton’s second law expressed in a general form that<br />

is useful for flow problems and maintains the restriction of zero viscosity. We will restrict our<br />

attention to steady flow so Euler’s equation in vector form becomes<br />

rg p r1V 2V<br />

(6.53)<br />

We wish to integrate this differential equation along some arbitrary streamline 1Fig. 6.122 and select<br />

the coordinate system with the z axis vertical 1with “up” being positive2 so that, as shown by the<br />

figure in the margin, the acceleration of gravity vector can be expressed as<br />

g gz<br />

where g is the magnitude of the acceleration of gravity vector. Also, it will be convenient to use<br />

the vector identity<br />

Equation 6.53 can now be written in the form<br />

and this equation can be rearranged to yield<br />

We next take the dot product of each term with a differential length ds along a streamline 1Fig.<br />

6.122. Thus,<br />

p<br />

r<br />

1V 2V 1 21V V2 V 1 V2<br />

rgz p r 1V V2 rV 1 V2<br />

2<br />

p<br />

r 1 2 1V 2 2 gz V 1 V2<br />

ds 1<br />

2 1V 2 2 ds gz ds 3V 1 V24 ds<br />

(6.54)<br />

Since ds has a direction along the streamline, the vectors ds and V are parallel. However, as shown<br />

by the figure in the margin, the vector V 1 V2 is perpendicular to V 1why?2, so it follows that<br />

3V 1 V24 ds 0<br />

Recall also that the dot product of the gradient of a scalar and a differential length gives the<br />

differential change in the scalar in the direction of the differential length. That is, with ds <br />

dx î dy ĵ dz kˆ we can write p ds 10p0x2 dx 10p0y2dy 10p0z2dz dp. Thus, Eq.<br />

6.54 becomes<br />

dp<br />

r 1 2 d1V 2 2 g dz 0<br />

(6.55)<br />

where the change in p, V, and z is along the streamline. Equation 6.55 can now be integrated to<br />

give<br />

dp (6.56)<br />

r V 2<br />

gz constant<br />

2<br />

which indicates that the sum of the three terms on the left side of the equation must remain a<br />

constant along a given streamline. Equation 6.56 is valid for both compressible and incompressible

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