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Problems 259<br />

5.110 The hydroelectric turbine shown in Fig. P5.110 passes 8 million<br />

gal/min across a head of 600 ft. What is the maximum amount of<br />

power output possible? Why will the actual amount be less?<br />

600 ft<br />

5.114 A centrifugal air compressor stage operates between an inlet<br />

stagnation pressure of 14.7 psia and an exit stagnation pressure<br />

of 60 psia. The inlet stagnation temperature is 80 °F. If the loss of<br />

total pressure through the compressor stage associated with irreversible<br />

flow phenomena is 10 psi, estimate the actual and ideal<br />

stagnation temperature rise through the compressor. Estimate the<br />

ratio of ideal to actual temperature rise to obtain an approximate<br />

value of the efficiency.<br />

5.115 Water is pumped through a 4-in.-diameter pipe as shown in<br />

Fig. P5.115a. The pump characteristics (pump head versus<br />

flowrate) are given in Fig. P5.115b. Determine the flowrate if the<br />

head loss in the pipe is h L 8V 2 2g.<br />

Turbine<br />

F I G U R E P5.110<br />

5.111 A pump is to move water from a lake into a large, pressurized<br />

tank as shown in Fig. P5.111 at a rate of 1000 gal in 10 min or<br />

less. Will a pump that adds 3 hp to the water work for this purpose?<br />

Support your answer with appropriate calculations. Repeat the problem<br />

if the tank were pressurized to 3, rather than 2, atmospheres.<br />

12 ft<br />

V<br />

Pump<br />

(a)<br />

h p , ft<br />

F I G U R E P5.115<br />

20<br />

16<br />

h p = 16 – 5Q<br />

12<br />

8<br />

4<br />

0<br />

0 1 2 3<br />

Q, ft 3 /s<br />

(b)<br />

20 ft<br />

Air<br />

p = 2 atm<br />

5.116 Water is pumped from the large tank shown in Fig. P5.116.<br />

The head loss is known to be equal to 4V 2 2g and the pump head is<br />

h , where h is in ft when Q is in ft 3 p 20 4Q 2<br />

p<br />

s. Determine the<br />

flowrate.<br />

Pump<br />

F I G U R E P5.111<br />

5.112 A hydraulic turbine is provided with 4.25 m 3 /s of water at<br />

415 kPa. A vacuum gage in the turbine discharge 3 m below the<br />

turbine inlet centerline reads 250 mm Hg vacuum. If the turbine<br />

shaft output power is 1100 kW, calculate the power loss through<br />

the turbine. The supply and discharge pipe inside diameters are<br />

identically 80 mm.<br />

5.113 Water is supplied at 150 ft 3 s and 60 psi to a hydraulic turbine<br />

through a 3-ft inside diameter inlet pipe as indicated in Fig.<br />

P5.113. The turbine discharge pipe has a 4-ft inside diameter. The<br />

static pressure at section 122, 10 ft below the turbine inlet, is 10-in.<br />

Hg vacuum. If the turbine develops 2500 hp, determine the power<br />

lost between sections 112 and 122.<br />

Section (1)<br />

p 1<br />

Q<br />

= 60 psi<br />

= 150 ft 3 /s<br />

D 1 = 3 ft<br />

13 ft<br />

Q V<br />

Pump<br />

Pipe area = 0.10 ft 2<br />

F I G U R E P5.116<br />

5.117 When a fan or pump is tested at the factory, head curves<br />

(head across the fan or pump versus volume flowrate) are often<br />

produced. A generic fan or pump head curve is shown in<br />

Fig.P5.117a. For any piping system, the drop in pressure or head<br />

involved because of loss can be estimated as a function of volume<br />

flowrate. A generic piping system loss curve is shown in<br />

Fig.P5.117b. When the pump or fan and piping system associated<br />

with the two curves of Fig.P5.117 are combined, what will the<br />

flowrate be? Why? How can the flowrate through this combined<br />

system be varied?<br />

10 ft<br />

Turbine<br />

p 2 = 10-in. Hg<br />

vacuum<br />

D 2 = 4 ft<br />

Section (2)<br />

H, Head across<br />

fan or pump<br />

Q, Volume flowrate<br />

(a)<br />

H, Head loss in<br />

piping system<br />

Q, Volume flowrate<br />

(b)<br />

F I G U R E P5.113<br />

F I G U R E P5.117

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