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204 Chapter 5 ■ Finite Control Volume Analysis<br />

z<br />

F A<br />

g<br />

D 1 = 16 mm<br />

x<br />

Control volume<br />

n<br />

Control volume<br />

w 1<br />

p 1<br />

A 1<br />

Section (1)<br />

w 1<br />

h = 30 mm<br />

z<br />

w<br />

w 2<br />

F I G U R E E5.11a<br />

D 2 = 5 mm<br />

Section (2)<br />

p 2 A 2<br />

w 2<br />

F I G U R E E5.11b<br />

F A = anchoring force that holds<br />

nozzle in place<br />

n = weight of nozzle<br />

w = weight of water contained in<br />

the nozzle<br />

p 1 = gage pressure at section (1)<br />

A 1 = cross section area at<br />

section (1)<br />

p 2 = gage pressure at section (2)<br />

A 2 = cross section area at<br />

section (2)<br />

w 1 = z direction velocity at<br />

control volume entrance<br />

w 2<br />

= z direction velocity at<br />

control volume exit<br />

<strong>fluid</strong> density, r, is constant throughout. Proceeding further we obtain<br />

for Eq. 1<br />

To complete this example we use quantities given in the<br />

problem statement to quantify the terms on the right-hand side<br />

1m # 121w 1 2 m # of Eq. 6.<br />

21w 2 2<br />

From Eq. 5.6,<br />

F A w n p 1 A 1 w p 2 A 2<br />

(3)<br />

where m # m # rw 1 A 1 rQ<br />

rAV is the mass flowrate.<br />

1999 kgm 3 210.6 liters2110 3 m 3 liter2<br />

Note that w 1 and w are used because both of these velocities<br />

are “down.” Also, m # 2<br />

0.599 kgs<br />

(7)<br />

1 is used because it is associated with<br />

flow into the control volume. Similarly, m # 2 is used because it is and<br />

associated with flow out of the control volume. Solving Eq. 3 for<br />

the anchoring force, F A , we obtain<br />

w 1 Q Q<br />

<br />

F A m # 1w 1 m # A 1 p1D142<br />

2<br />

2w 2 w n p 1 A 1 w p 2 A 2 (4)<br />

From the conservation of mass equation, Eq. 5.12, we obtain<br />

<br />

10.6 liter s2110 3 m 3 liter2<br />

(8)<br />

p116 mm2 2 411000 2 mm 2 m 2 2 2.98 m s<br />

m # 1 m # 2 m #<br />

(5) Also from Eq. 5.6,<br />

which when combined with Eq. 4 gives<br />

F A m # 1w 1 w 2 2 w n p 1 A 1 w w p 2 A 2<br />

It is instructive to note how the anchoring force is affected<br />

by the different actions involved. As expected, the nozzle<br />

weight, w n , the water weight, w , and gage pressure force at<br />

section 112, p 1 A 1 , all increase the anchoring force, while the<br />

gage pressure force at section 122, p 2 A 2 , acts to decrease the<br />

anchoring force. The change in the vertical momentum<br />

flowrate, m # 1w 1 w 2 2, will, in this instance, decrease the anchoring<br />

force because this change is negative 1w 2 7 w 1 2.<br />

(6)<br />

w 2 Q <br />

Q<br />

A 2 p1D 2 242<br />

<br />

10.6 liter s2110 3 m 3 liter2<br />

p15 mm2 2 411000 2 mm 2 m 2 2 30.6 m s<br />

The weight of the nozzle, w n , can be obtained from the nozzle<br />

mass, m n , with<br />

w n m n g 10.1 kg219.81 ms 2 2 0.981 N<br />

(9)<br />

(10)<br />

The weight of the water in the control volume, w , can be obtained<br />

from the water density, r, and the volume of water, V w , in

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