fluid_mechanics
160 Chapter 4 ■ Fluid Kinematics Water heater Hot T out > T in Pathline ___ ∂T = 0 ∂ t DT ___ Dt ≠ 0 Cold T in F I G U R E 4.6 Steady-state operation of a water heater. (Photo courtesy of American Water Heater Company.) u 0 a x 0 The convective derivative is a result of the spatial variation of the flow. x x It is due to the convection, or motion, of the particle through space in which there is a gradient 3 § 1 2 01 20x î 01 20y ĵ 01 20z kˆ4 in the parameter value. That portion of the acceleration given by the term 1V § 2V is termed the convective acceleration. As is illustrated in Fig. 4.6, the temperature of a water particle changes as it flows through a water heater. The water entering the heater is always the same cold temperature and the water leaving the heater is always the same hot temperature. The flow is steady. However, the temperature, T, of each water particle increases as it passes through the heater— T out 7 T in . Thus, DTDt 0 because of the convective term in the total derivative of the temperature. That is, 0T0t 0, but u 0T0x 0 1where x is directed along the streamline2, since there is a nonzero temperature gradient along the streamline. A fluid particle traveling along this nonconstant temperature path 10T0x 02 at a specified speed 1u2 will have its temperature change with time at a rate of DTDt u 0T0x even though the flow is steady 10T0t 02. The same types of processes are involved with fluid accelerations. Consider flow in a variable area pipe as shown in Fig. 4.7. It is assumed that the flow is steady and one-dimensional with velocity that increases and decreases in the flow direction as indicated. As the fluid flows from section 112 to section 122, its velocity increases from V 1 to V 2 . Thus, even though 0V0t 0 1steady flow2, fluid particles experience an acceleration given by a x u 0u0x 1convective acceleration2. For x 1 6 x 6 x 2 , it is seen that 0u0x 7 0 so that a x 7 0—the fluid accelerates. For x 2 6 x 6 x 3 , it is seen that 0u0x 6 0 so that a x 6 0—the fluid decelerates. This acceleration and deceleration are shown in the figure in the margin. If V 1 V 3 , the amount of acceleration precisely balances the amount of deceleration even though the distances between x 2 and x 1 and x 3 and x 2 are not the same. The concept of the material derivative can be used to determine the time rate of change of any parameter associated with a particle as it moves about. Its use is not restricted to fluid mechanics alone. The basic ingredients needed to use the material derivative concept are the field description of the parameter, P P1x, y, z, t2, and the rate at which the particle moves through that field, V V 1x, y, z, t2. u = V 1 u = V 2 > V 1 x x 2 1 F I G U R E 4.7 area pipe. u = V 3 = V 1 < V 2 x 3 Uniform, steady flow in a variable x
4.2 The Acceleration Field 161 E XAMPLE 4.5 Acceleration from a Given Velocity Field GIVEN Consider the steady, two-dimensional flow field discussed in Example 4.2. FIND Determine the acceleration field for this flow. SOLUTION In general, the acceleration is given by a DV Dt 0V 0t 0V 0t 1V § 21V2 u 0V 0x v 0V 0y w 0V 0z (1) y V a Streamline where the velocity is given by V 1V 0/21xî yĵ2 so that u 1V 0/2 x and v 1V 0/2y. For steady 3 01 20t 04, twodimensional 3w 0 and 01 20z 04 flow, Eq. l becomes a u 0V 0x v 0V 0y au 0u 0x v 0u 0v b î au 0y 0x v 0v 0y b ĵ Hence, for this flow the acceleration is given by F I G U R E E4.5 x or a ca V 0 / b 1x2 aV 0 / b aV 0 / b 1y2102d î ca V 0 / b 1x2102 aV 0 / b 1y2 aV 0 / bd ĵ a x V 2 0 x / , a 2 y V 2 0 y / 2 (Ans) COMMENTS The fluid experiences an acceleration in both the x and y directions. Since the flow is steady, there is no local acceleration—the fluid velocity at any given point is constant in time. However, there is a convective acceleration due to the change in velocity from one point on the particle’s pathline to another. Recall that the velocity is a vector—it has both a magnitude and a direction. In this flow both the fluid speed 1magnitude2 and flow direction change with location 1see Fig. E4.1a2. For this flow the magnitude of the acceleration is constant on circles centered at the origin, as is seen from the fact that Also, the acceleration vector is oriented at an angle u from the x axis, where tan u a y a x y x This is the same angle as that formed by a ray from the origin to point 1x, y2. Thus, the acceleration is directed along rays from the origin and has a magnitude proportional to the distance from the origin. Typical acceleration vectors 1from Eq. 22 and velocity vectors 1from Example 4.12 are shown in Fig. E4.5 for the flow in the first quadrant. Note that a and V are not parallel except along the x and y axes 1a fact that is responsible for the curved pathlines of the flow2, and that both the acceleration and velocity are zero at the origin 1x y 02. An infinitesimal fluid particle placed precisely at the origin will remain there, but its neighbors 1no matter how close they are to the origin2 will drift away. 0a 0 1a x 2 a y 2 a z 2 2 1 2 a V 0 / b 2 1x 2 y 2 2 1 2 (2) E XAMPLE 4.6 The Material Derivative GIVEN A fluid flows steadily through a two-dimensional nozzle of length / as shown in Fig. E4.6a. The nozzle shape is given by y/ ; 0.5 31 1x/24 If viscous and gravitational effects are negligible, the velocity field is approximately u V 0 1 x/, v V 0 y/ (1)
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160 Chapter 4 ■ Fluid Kinematics<br />
Water<br />
heater<br />
Hot<br />
T out > T in<br />
Pathline<br />
___ ∂T<br />
= 0<br />
∂ t<br />
DT ___<br />
Dt<br />
≠ 0<br />
Cold<br />
T in<br />
F I G U R E 4.6 Steady-state<br />
operation of a water heater. (Photo courtesy<br />
of American Water Heater Company.)<br />
u<br />
0<br />
a x<br />
0<br />
The convective derivative<br />
is a result<br />
of the spatial variation<br />
of the flow.<br />
x<br />
x<br />
It is due to the convection, or motion, of the particle through space in which there is a gradient<br />
3 § 1 2 01 20x î 01 20y ĵ 01 20z kˆ4 in the parameter value. That portion of the acceleration<br />
given by the term 1V § 2V is termed the convective acceleration.<br />
As is illustrated in Fig. 4.6, the temperature of a water particle changes as it flows through<br />
a water heater. The water entering the heater is always the same cold temperature and the water<br />
leaving the heater is always the same hot temperature. The flow is steady. However, the temperature,<br />
T, of each water particle increases as it passes through the heater— T out 7 T in . Thus, DTDt 0<br />
because of the convective term in the total derivative of the temperature. That is, 0T0t 0, but<br />
u 0T0x 0 1where x is directed along the streamline2, since there is a nonzero temperature gradient<br />
along the streamline. A <strong>fluid</strong> particle traveling along this nonconstant temperature path 10T0x 02<br />
at a specified speed 1u2 will have its temperature change with time at a rate of DTDt u 0T0x<br />
even though the flow is steady 10T0t 02.<br />
The same types of processes are involved with <strong>fluid</strong> accelerations. Consider flow in a variable<br />
area pipe as shown in Fig. 4.7. It is assumed that the flow is steady and one-dimensional with<br />
velocity that increases and decreases in the flow direction as indicated. As the <strong>fluid</strong> flows from<br />
section 112 to section 122, its velocity increases from V 1 to V 2 . Thus, even though 0V0t 0 1steady<br />
flow2, <strong>fluid</strong> particles experience an acceleration given by a x u 0u0x 1convective acceleration2.<br />
For x 1 6 x 6 x 2 , it is seen that 0u0x 7 0 so that a x 7 0—the <strong>fluid</strong> accelerates. For x 2 6 x 6 x 3 ,<br />
it is seen that 0u0x 6 0 so that a x 6 0—the <strong>fluid</strong> decelerates. This acceleration and deceleration<br />
are shown in the figure in the margin. If V 1 V 3 , the amount of acceleration precisely balances<br />
the amount of deceleration even though the distances between x 2 and x 1 and x 3 and x 2 are not the<br />
same.<br />
The concept of the material derivative can be used to determine the time rate of change of<br />
any parameter associated with a particle as it moves about. Its use is not restricted to <strong>fluid</strong> <strong>mechanics</strong><br />
alone. The basic ingredients needed to use the material derivative concept are the field description<br />
of the parameter, P P1x, y, z, t2, and the rate at which the particle moves through that field,<br />
V V 1x, y, z, t2.<br />
u = V 1<br />
u = V 2 > V 1<br />
x<br />
x 2<br />
1<br />
F I G U R E 4.7<br />
area pipe.<br />
u = V 3 = V 1 < V 2<br />
x 3<br />
Uniform, steady flow in a variable<br />
x