fluid_mechanics
128 Chapter 3 ■ Elementary Fluid Dynamics—The Bernoulli Equation Thus, a “rule of thumb” is that the flow of a perfect gas may be considered as incompressible provided the Mach number is less than about 0.3. In standard air 1T 1 59 °F, c 1 1kRT 1 1117 fts2 this corresponds to a speed of V 1 Ma 1 c 1 0.311117 fts2 335 fts 228 mihr. At higher speeds, compressibility may become important. E XAMPLE 3.15 Compressible Flow—Mach Number GIVEN The jet shown in Fig. E3.15 flies at Mach 0.82 at an altitude of 10 km in a standard atmosphere. FIND Determine the stagnation pressure on the leading edge of its wing if the flow is incompressible; and if the flow is compressible isentropic. SOLUTION From Tables 1.8 and C.2 we find that p 1 26.5 kPa 1abs2, T r 0.414 kgm 3 1 49.9 °C, , and k 1.4. Thus, if we assume incompressible flow, Eq. 3.26 gives or (Ans) On the other hand, if we assume isentropic flow, Eq. 3.25 gives or p 2 p 1 kMa2 1 1.4 10.8222 0.471 p 1 2 2 p 2 p 1 0.471126.5 kPa2 12.5 kPa p 2 p 1 11.4 12 1.411.412 ec1 10.822 2 d 1 f p 1 2 0.555 p 2 p 1 0.555 126.5 kPa2 14.7 kPa (Ans) COMMENT We see that at Mach 0.82 compressibility effects are of importance. The pressure 1and, to a first approximation, the F I G U R E E3.15 Pure stock/superstock.) (Photograph courtesy of lift and drag on the airplane; see Chapter 92 is approximately 14.712.5 1.18 times greater according to the compressible flow calculations. This may be very significant. As discussed in Chapter 11, for Mach numbers greater than 1 1supersonic flow2 the differences between incompressible and compressible results are often not only quantitative but also qualitative. Note that if the airplane were flying at Mach 0.30 1rather than 0.822 the corresponding values would be p 2 p 1 1.670 kPa for incompressible flow and p 2 p 1 1.707 kPa for compressible flow. The difference between these two results is about 2%. The Bernoulli equation can be modified for unsteady flows. 3.8.2 Unsteady Effects Another restriction of the Bernoulli equation 1Eq. 3.72 is the assumption that the flow is steady. For such flows, on a given streamline the velocity is a function of only s, the location along the streamline. That is, along a streamline V V1s2. For unsteady flows the velocity is also a function of time, so that along a streamline V V1s, t2. Thus when taking the time derivative of the velocity to obtain the streamwise acceleration, we obtain a s 0V0t V 0V0s rather than just a s V 0V0s as is true for steady flow. For steady flows the acceleration is due to the change in velocity resulting from a change in position of the particle 1the V 0V0s term2, whereas for unsteady flow there is an additional contribution to the acceleration resulting from a change in velocity with time at a fixed location 1the 0V0t term2. These effects are discussed in detail in Chapter 4. The net effect is that the inclusion of the unsteady term, 0V0t, does not allow the equation of motion to be easily integrated 1as was done to obtain the Bernoulli equation2 unless additional assumptions are made. The Bernoulli equation was obtained by integrating the component of Newton’s second law 1Eq. 3.52 along the streamline. When integrated, the acceleration contribution to this equation, the
3.8 Restrictions on Use of the Bernoulli Equation 129 V3.11 Oscillations in a U-tube 1 2 rd1V 2 2 term, gave rise to the kinetic energy term in the Bernoulli equation. If the steps leading to Eq. 3.5 are repeated with the inclusion of the unsteady effect 10V0t 02 the following is obtained: r 0V 0t ds dp 1 2 rd1V 2 2 g dz 0 For incompressible flow this can be easily integrated between points 112 and 122 to give p 1 1 2 rV 2 1 gz 1 r s 2 s 1 0V 0t ds p 2 1 2 rV 2 2 gz 2 1along a streamline2 1along a streamline2 (3.27) Equation 3.27 is an unsteady form of the Bernoulli equation valid for unsteady, incompressible, inviscid flow. Except for the integral involving the local acceleration, 0V0t, it is identical to the steady Bernoulli equation. In general, it is not easy to evaluate this integral because the variation of 0V0t along the streamline is not known. In some situations the concepts of “irrotational flow” and the “velocity potential” can be used to simplify this integral. These topics are discussed in Chapter 6. E XAMPLE 3.16 Unsteady Flow—U-Tube GIVEN An incompressible, inviscid liquid is placed in a vertical, constant diameter U-tube as indicated in Fig. E3.16. When released from the nonequilibrium position shown, the liquid column will oscillate at a specific frequency. FIND SOLUTION Determine this frequency. The frequency of oscillation can be calculated by use of Eq. 3.27 as follows. Let points 112 and 122 be at the air–water interfaces of the two columns of the tube and z 0 correspond to the equilibrium position of these interfaces. Hence, p 1 p 2 0 and if z 2 z, then z 1 z. In general, z is a function of time, z z1t2. For a constant diameter tube, at any instant in time the fluid speed is constant throughout the tube, V 1 V 2 V, and the integral representing the unsteady effect in Eq. 3.27 can be written as s 2 s 1 0V dV ds 0t dt s 2 where / is the total length of the liquid column as shown in the figure. Thus, Eq. 3.27 can be written as g1z2 r/ dV dt gz Since V dzdt and g rg, this can be written as the secondorder differential equation describing simple harmonic motion s 1 d 2 z 2 dt 2g / z 0 ds / dV dt g Open tube V 2 (2) z z = 0 Equilibrium (1) position V 1 F I G U R E E3.16 which has the solution z1t2 C 1 sin1 12g/ t2 C 2 cos 1 12g/ t2. The values of the constants C 1 and C 2 depend on the initial state 1velocity and position2 of the liquid at t 0. Thus, the liquid oscillates in the tube with a frequency v 22g/ (Ans) COMMENT This frequency depends on the length of the column and the acceleration of gravity 1in a manner very similar to the oscillation of a pendulum2. The period of this oscillation 1the time required to complete an oscillation2 is t 0 2p1/2g. In a few unsteady flow cases, the flow can be made steady by an appropriate selection of the coordinate system. Example 3.17 illustrates this.
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3.8 Restrictions on Use of the Bernoulli Equation 129<br />
V3.11 Oscillations<br />
in a U-tube<br />
1<br />
2 rd1V 2 2 term, gave rise to the kinetic energy term in the Bernoulli equation. If the steps leading<br />
to Eq. 3.5 are repeated with the inclusion of the unsteady effect 10V0t 02 the following is<br />
obtained:<br />
r 0V<br />
0t ds dp 1 2 rd1V 2 2 g dz 0<br />
For incompressible flow this can be easily integrated between points 112 and 122 to give<br />
p 1 1 2 rV 2 1 gz 1 r <br />
s 2<br />
s 1<br />
0V<br />
0t ds p 2 1 2 rV 2 2 gz 2<br />
1along a streamline2<br />
1along a streamline2<br />
(3.27)<br />
Equation 3.27 is an unsteady form of the Bernoulli equation valid for unsteady, incompressible,<br />
inviscid flow. Except for the integral involving the local acceleration, 0V0t, it is identical to the<br />
steady Bernoulli equation. In general, it is not easy to evaluate this integral because the variation<br />
of 0V0t along the streamline is not known. In some situations the concepts of “irrotational flow”<br />
and the “velocity potential” can be used to simplify this integral. These topics are discussed in<br />
Chapter 6.<br />
E XAMPLE 3.16<br />
Unsteady Flow—U-Tube<br />
GIVEN An incompressible, inviscid liquid is placed in a vertical,<br />
constant diameter U-tube as indicated in Fig. E3.16. When<br />
released from the nonequilibrium position shown, the liquid<br />
column will oscillate at a specific frequency.<br />
FIND<br />
SOLUTION<br />
Determine this frequency.<br />
The frequency of oscillation can be calculated by use of Eq. 3.27<br />
as follows. Let points 112 and 122 be at the air–water interfaces of<br />
the two columns of the tube and z 0 correspond to the equilibrium<br />
position of these interfaces. Hence, p 1 p 2 0 and if<br />
z 2 z, then z 1 z. In general, z is a function of time, z z1t2.<br />
For a constant diameter tube, at any instant in time the <strong>fluid</strong> speed<br />
is constant throughout the tube, V 1 V 2 V, and the integral<br />
representing the unsteady effect in Eq. 3.27 can be written as<br />
s 2<br />
s 1<br />
0V dV<br />
ds <br />
0t dt s 2<br />
where / is the total length of the liquid column as shown in the<br />
figure. Thus, Eq. 3.27 can be written as<br />
g1z2 r/ dV<br />
dt gz<br />
Since V dzdt and g rg, this can be written as the secondorder<br />
differential equation describing simple harmonic motion<br />
s 1<br />
d 2 z<br />
2<br />
dt<br />
2g<br />
/ z 0<br />
ds / dV<br />
dt<br />
g<br />
Open<br />
tube<br />
<br />
V 2<br />
(2)<br />
z<br />
z = 0<br />
Equilibrium<br />
(1)<br />
position<br />
V 1<br />
F I G U R E E3.16<br />
which has the solution z1t2 C 1 sin1 12g/ t2 C 2 cos<br />
1 12g/ t2. The values of the constants C 1 and C 2 depend on the<br />
initial state 1velocity and position2 of the liquid at t 0. Thus, the<br />
liquid oscillates in the tube with a frequency<br />
v 22g/<br />
(Ans)<br />
COMMENT This frequency depends on the length of the column<br />
and the acceleration of gravity 1in a manner very similar to<br />
the oscillation of a pendulum2. The period of this oscillation 1the<br />
time required to complete an oscillation2 is t 0 2p1/2g.<br />
In a few unsteady flow cases, the flow can be made steady by an appropriate selection of the<br />
coordinate system. Example 3.17 illustrates this.