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Problems 83<br />

8 psi<br />

Carbon tetrachloride<br />

A<br />

B<br />

0.7 ft<br />

Oil<br />

Brine<br />

3 ft<br />

1 ft<br />

Water<br />

h<br />

Brine<br />

12 in.<br />

1 ft<br />

Carbon<br />

tetrachloride<br />

F I G U R E P2.41<br />

θ<br />

reservoir on the left, which contains carbon tetrachloride, is closed<br />

and pressurized to 8 psi. The reservoir on the right contains water<br />

and is open to the atmosphere. With the given data, determine the<br />

depth of water, h, in the right reservoir.<br />

2.42 Determine the pressure of the water in pipe A shown in Fig.<br />

P2.42 if the gage pressure of the air in the tank is 2 psi.<br />

Air<br />

p = 2 psi<br />

1 ft<br />

4 ft<br />

2 ft<br />

Water<br />

F I G U R E P2.42<br />

SG = 0.9<br />

2.43 In Fig. P2.43 pipe A contains gasoline 1SG 0.72, pipe B<br />

contains oil 1SG 0.92, and the manometer <strong>fluid</strong> is mercury.<br />

Determine the new differential reading if the pressure in pipe A is<br />

decreased 25 kPa, and the pressure in pipe B remains constant. The<br />

initial differential reading is 0.30 m as shown.<br />

A<br />

F I G U R E P2.44<br />

2.45 Determine the new differential reading along the inclined leg<br />

of the mercury manometer of Fig. P2.45, if the pressure in pipe A<br />

is decreased 10 kPa and the pressure in pipe B remains unchanged.<br />

The <strong>fluid</strong> in A has a specific gravity of 0.9 and the <strong>fluid</strong> in B is<br />

water.<br />

A<br />

SG = 0.9<br />

30°<br />

100 mm<br />

50 mm<br />

F I G U R E P2.45<br />

Water<br />

Mercury<br />

2.46 Determine the change in the elevation of the mercury in the<br />

left leg of the manometer of Fig. P2.46 as a result of an increase<br />

in pressure of 5 psi in pipe A while the pressure in pipe B remains<br />

constant.<br />

A<br />

Water<br />

18 in.<br />

6 in.<br />

Oil (SG = 0.9)<br />

B<br />

B<br />

80 mm<br />

12 in.<br />

A<br />

0.4 m<br />

Oil<br />

B<br />

30°<br />

1_<br />

in.<br />

2<br />

diameter Mercury<br />

F I G U R E P2.46<br />

1_<br />

in. diameter<br />

4<br />

Gasoline<br />

0.3 m<br />

Mercury<br />

2.47 The U-shaped tube shown in Fig. P2.47 initially contains<br />

water only. A second liquid with specific weight, g, less than water<br />

is placed on top of the water with no mixing occurring. Can the<br />

F I G U R E P2.43<br />

2.44 The inclined differential manometer of Fig. P2.44 contains<br />

carbon tetrachloride. Initially the pressure differential between<br />

pipes A and B, which contain a brine 1SG 1.12, is zero as<br />

illustrated in the figure. It is desired that the manometer give a<br />

differential reading of 12 in. (measured along the inclined tube)<br />

for a pressure differential of 0.1 psi. Determine the required angle<br />

of inclination, u.<br />

γ<br />

h<br />

D 1 = 1.5 D 2<br />

D 2<br />

Water<br />

F I G U R E P2.47

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