Refrigeration & Air Conditioning Technology 7th Edition
Unit 12 Basic Electricity and Magnetism 289 E = 120 V SAFETY PRECAUTION: Do not use any electrical measuring instruments without specific instructions from a qualified person. Follow the manufacturer’s instructions. The use of electrical measuring instruments is discussed in Section 12.19.• 12.11 CHARACTERISTICS OF SERIES CIRCUITS A 20 Ω 10 Ω In series circuits, • the voltage is divided across the different resistances. The mathematical formula is as follows: E total E 1 E 2 E 3 . . . • the total current flows through each resistance or load. The mathematical formula is as follows: I total I 1 I 2 I 3 . . . • the resistances are added together to obtain the total resistance. The formula for calculating total resistance in a series circuit is as follows: R total R 1 R 2 R 3 . . . 10 Ω Figure 12.20 The current in a series circuit has only one possible path to follow. A OHMMETER Figure 12.21 To determine the resistance of a circuit component, turn off the power and disconnect the component from the circuit. Then, check the component with an ohmmeter. O © Cengage Learning 2013 © Cengage Learning 2013 12.12 CHARACTERISTICS OF PARALLEL CIRCUITS In parallel circuits, • the total voltage is applied across each resistance. The mathematical formula is as follows: E total E 1 E 2 E 3 . . . • the current is divided between the different loads according to their individual resistances, and the total current is equal to the sum of the currents in each branch. The mathematical formula is as follows: I total I 1 I 2 I 3 . . . • the total resistance is less than the value of the smallest resistance. As more and more resistive paths or branches are added to the parallel circuit, the total resistance of the circuit gets lower and lower. Calculating the total resistance in a parallel circuit requires a different procedure than simply adding them together, as in a series circuit. A parallel circuit allows current flow along two or more paths at the same time. This type of circuit applies equal voltage to all loads. The general formula used to determine total resistance in parallel circuits is as follows: For two resistances R R R R R total 1 2 1 2 For more than two resistances R total 1 1 1 1 ... R R R R 1 2 3 The total resistance of the circuit in Figure 12.22 is determined as follows: 1 R total 1 1 1 10 20 30 1 01 . 005 . 0. 033 1 0. 183 5.46 120 V 22 A A 10 Ω 20 Ω 30 Ω Figure 12.22 The total resistance of this circuit can be determined using the information in the diagram. © Cengage Learning 2013
290 Section 3 Basic Automatic Controls Notice that the total resistance of 5.46 Ω is lower than the lowest individual resistance in the circuit. Another way to look at the resistance calculation is as follows: 1 1 1 1 R R R R total 1 2 3 1 1 1 1 R 10 20 30 total 1 6 3 2 R 60 60 60 total 1 11 R 60 total 60 R total 11 R 5. 46 total To determine the total current draw, use Ohm’s law: E I R 120V 546 22 A We can confirm this value for the total current in the circuit by determining the current flow through the individual loads or resistances and then adding them up. The current flow through the 10-Ω resistance is determined here: I 10 E R I 10 120 V 10 Ω 12 A The current flow through the 20-Ω resistance is determined here: I 20 E R I 20 120 V 20 Ω 6 A The current flow through the 30-Ω resistance is determined here: I 30 E R I 30 120 V 30 Ω 4 A By adding these three individual branch currents together, we get I total I 1 I 2 I 3 I total 12 A 6 A 4 A I total 22 A 12.13 ELECTRICAL POWER Electrical power (P) is measured in watts. A watt (W) is the power used when 1 ampere flows with a potential difference of 1 volt. Therefore, power can be determined by multiplying the voltage times the amperes flowing in a circuit. Watts Volts Amperes or P E I The consumer of electrical power pays the electrical utility company according to the number of kilowatts (kW) used for a certain time span, usually billed as kilowatt hours (kWh). A kilowatt is equal to 1000 W. To determine the power being consumed, divide the number of watts by 1000: E I P (inkW) 1000 In the circuit shown in Figure 12.22, the power consumed can be calculated as follows: P E I P 120 V 22 A 2640 W kW P 1000 kW 2640 W 1000 2.64 kW 12.14 MAGNETISM Magnetism was briefly discussed earlier in the unit to explain how electrical generators are able to produce electricity. Magnets are classified as either permanent or temporary. Permanent magnets are used in only a few applications that air-conditioning and refrigeration technicians would work with, but electromagnets, a type of temporary magnet, are used in many electrical components of air-conditioning and refrigeration equipment. A magnetic field is generated around a wire whenever an electrical current is flowing through it, Figure 12.23. If the wire or conductor is formed into a loop, the strength of the magnetic field will be increased, Figure 12.24, and if the wire is wound into a coil, a stronger magnetic field will be created, Figure 12.25. This coil of wire carrying an electrical current is called a solenoid. This solenoid or electromagnet will attract or pull an iron bar into the coil, Figure 12.26. If an iron bar is inserted permanently in the coil, the strength of the magnetic field will be increased even more. The magnetic field can be used to generate electricity and to cause electric motors to operate. The magnetic attraction CROSS SECTION OF CONDUCTOR CARRYING CURRENT MAGNETIC FIELD AROUND CONDUCTOR Figure 12.23 This cross section of a wire shows a magnetic field around the conductor. © Cengage Learning 2013
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290 Section 3 Basic Automatic Controls<br />
Notice that the total resistance of 5.46 Ω is lower than the<br />
lowest individual resistance in the circuit. Another way to<br />
look at the resistance calculation is as follows:<br />
1 1 1 1<br />
<br />
R R R R<br />
total 1 2 3<br />
1 1 1 1<br />
<br />
R 10 20 30<br />
total<br />
1 6 3 2<br />
<br />
R 60 60 60<br />
total<br />
1 11<br />
<br />
R 60<br />
total<br />
60<br />
R <br />
total<br />
11<br />
R 5. 46 <br />
total<br />
To determine the total current draw, use Ohm’s law:<br />
E<br />
I R<br />
120V<br />
546<br />
22 A<br />
<br />
We can confirm this value for the total current in the circuit<br />
by determining the current flow through the individual<br />
loads or resistances and then adding them up. The current<br />
flow through the 10-Ω resistance is determined here:<br />
I 10<br />
E R<br />
I 10<br />
120 V 10 Ω 12 A<br />
The current flow through the 20-Ω resistance is determined<br />
here:<br />
I 20<br />
E R<br />
I 20<br />
120 V 20 Ω 6 A<br />
The current flow through the 30-Ω resistance is determined<br />
here:<br />
I 30<br />
E R<br />
I 30<br />
120 V 30 Ω 4 A<br />
By adding these three individual branch currents together,<br />
we get<br />
I total<br />
I 1<br />
I 2<br />
I 3<br />
I total<br />
12 A 6 A 4 A<br />
I total<br />
22 A<br />
12.13 ELECTRICAL POWER<br />
Electrical power (P) is measured in watts. A watt (W) is the<br />
power used when 1 <strong>amp</strong>ere flows with a potential difference<br />
of 1 volt. Therefore, power can be determined by multiplying<br />
the voltage times the <strong>amp</strong>eres flowing in a circuit.<br />
Watts Volts Amperes<br />
or<br />
P E I<br />
The consumer of electrical power pays the electrical<br />
utility company according to the number of kilowatts<br />
(kW) used for a certain time span, usually billed as kilowatt<br />
hours (kWh). A kilowatt is equal to 1000 W. To determine<br />
the power being consumed, divide the number of watts by<br />
1000:<br />
E I<br />
P (inkW)<br />
1000<br />
In the circuit shown in Figure 12.22, the power consumed<br />
can be calculated as follows:<br />
P E I<br />
P 120 V 22 A 2640 W<br />
kW P 1000<br />
kW 2640 W 1000 2.64 kW<br />
12.14 MAGNETISM<br />
Magnetism was briefly discussed earlier in the unit to explain<br />
how electrical generators are able to produce electricity.<br />
Magnets are classified as either permanent or temporary.<br />
Permanent magnets are used in only a few applications that<br />
air-conditioning and refrigeration technicians would work<br />
with, but electromagnets, a type of temporary magnet, are<br />
used in many electrical components of air-conditioning and<br />
refrigeration equipment.<br />
A magnetic field is generated around a wire whenever<br />
an electrical current is flowing through it, Figure 12.23. If<br />
the wire or conductor is formed into a loop, the strength of<br />
the magnetic field will be increased, Figure 12.24, and if the<br />
wire is wound into a coil, a stronger magnetic field will be<br />
created, Figure 12.25. This coil of wire carrying an electrical<br />
current is called a solenoid. This solenoid or electromagnet<br />
will attract or pull an iron bar into the coil, Figure 12.26. If<br />
an iron bar is inserted permanently in the coil, the strength<br />
of the magnetic field will be increased even more.<br />
The magnetic field can be used to generate electricity and<br />
to cause electric motors to operate. The magnetic attraction<br />
CROSS SECTION OF CONDUCTOR<br />
CARRYING CURRENT<br />
MAGNETIC FIELD<br />
AROUND CONDUCTOR<br />
Figure 12.23 This cross section of a wire shows a magnetic field around<br />
the conductor.<br />
© Cengage Learning 2013