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66 MATHEMATICS<br />

t<br />

2<br />

Let t 2<br />

be the time, in hours, taken by the boat to go 44 km downstream. Then<br />

44 . The total time taken, t 1<br />

+ t 2<br />

, is 10 hours. Therefore, we get the equation<br />

x y<br />

✁<br />

30 44<br />

= 10 ✁<br />

(1)<br />

✂<br />

✁ x y x y<br />

In the second case, in 13 hours it can go 40 km upstream and 55 km downstream. We<br />

get the equation<br />

Put<br />

40 55<br />

✁<br />

x y x y<br />

1 1<br />

u and<br />

x y x y<br />

✂<br />

✂<br />

✁<br />

✁<br />

= 13 (2)<br />

v<br />

On substituting these values in Equations (1) and (2), we get the pair of linear<br />

equations:<br />

30u + 44v = 10 or 30u + 44v – 10 = 0 (4)<br />

40u + 55v = 13 or 40u + 55v – 13 = 0 (5)<br />

Using Cross-multiplication method, we get<br />

u<br />

v<br />

1<br />

=<br />

44( 13) 55( 10) 40( 10) 30( 13) 30(55) 44(40)<br />

u v 1<br />

i.e.,<br />

☎ =<br />

22 ✄ ✄ 10 ✄<br />

110<br />

i.e., u = 1 , v = 1<br />

5 11<br />

Now put these values of u and v in Equations (3), we get<br />

✂ ✂ ✂<br />

✂ ✂ ✂ ✂<br />

✂<br />

✁<br />

1 1 1 1<br />

and<br />

x y 5 x y 11<br />

i.e., x – y = 5 and x + y = 11 (6)<br />

Adding these equations, we get<br />

2x =16<br />

i.e., x =8<br />

Subtracting the equations in (6), we get<br />

2y =6<br />

i.e., y =3<br />

(3)

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