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You know that p = 1 x and q = 1 y ✁<br />

64 MATHEMATICS<br />

These equations are not in the form ax + by + c = 0. However, if we substitute<br />

1 1<br />

p and<br />

x y<br />

q<br />

in Equations (1) and (2), we get<br />

2p + 3q = 13 (3)<br />

5p – 4q = – 2 (4)<br />

So, we have expressed the equations as a pair of linear equations. Now, you can use<br />

any method to solve these equations, and get p = 2, q = 3.<br />

Substitute the values of p and q to get<br />

1 1 1 1<br />

2, i.e., x and 3, i.e., y<br />

x<br />

2 y<br />

3<br />

.<br />

1 1<br />

Verification : By substituting x and ✂ ✂ y in the given equations, we find that<br />

2 3<br />

both the equations are satisfied.<br />

Example 18 : Solve the following pair of equations by reducing them to a pair of<br />

linear equations :<br />

5 1<br />

=2<br />

✄<br />

x☎<br />

☎ 1 y 2<br />

6 3<br />

=1 ✆<br />

x 1 y 2<br />

✆<br />

✆<br />

Solution : Let us put<br />

1 1<br />

p and ✝<br />

✝ q<br />

x 1 y 2<br />

. Then the given equations<br />

1 ✞ ✟ 1<br />

5 ✠ ✡ ☛<br />

x 1 y 2<br />

= 2 (1)<br />

☎<br />

☎<br />

1 ✎ ✏ ✎ ✏ 1<br />

6 ✑ ✒ ✓ ✒ ✓ 3<br />

✕ ✔ ✕ x 1 y<br />

✔ 2<br />

= 1 (2)<br />

✌<br />

☞<br />

✍<br />

☞<br />

can be written as : 5p + q = 2 (3)<br />

6p – 3q = 1 (4)<br />

✑<br />

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