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So, the value of x 2 – 3 is zero when x = 3 or x = – 3☞<br />

30 MATHEMATICS<br />

b (Coefficient of x)<br />

✂<br />

i.e., sum of zeroes = + ✁ =<br />

2<br />

a Coefficient of x<br />

✂ ✄ ,<br />

product of zeroes = ✁ =<br />

Let us consider some examples.<br />

c<br />

a<br />

Constant term<br />

Coefficient of x<br />

☎ .<br />

2<br />

Example 2 : Find the zeroes of the quadratic polynomial x 2 + 7x + 10, and verify the<br />

relationship between the zeroes and the coefficients.<br />

Solution : We have<br />

x 2 + 7x + 10 = (x + 2)(x + 5)<br />

So, the value of x 2 + 7x + 10 is zero when x + 2 = 0 or x + 5 = 0, i.e., when x = – 2 or<br />

x = –5. Therefore, the zeroes of x 2 + 7x + 10 are – 2 and – 5. Now,<br />

(7) – (Coefficient of x<br />

✂<br />

)<br />

sum of zeroes = ✆ –2 ✄ (–5) ✄ ✄<br />

–(7)<br />

,<br />

2<br />

1 Coefficient of x<br />

10 Constant term<br />

product of zeroes = ( 2) ( 5) 10<br />

2<br />

1 Coefficient of x<br />

✂ ✝ ✂ ✄ ✄ ✄ ✞<br />

Example 3 : Find the zeroes of the polynomial x 2 – 3 and verify the relationship<br />

between the zeroes and the coefficients.<br />

Solution : Recall the identity a 2 – b 2 = (a – b)(a + b). Using it, we can write:<br />

x<br />

x 2 – 3 ✟ ✠ ✟ ✠<br />

= 3 x 3<br />

✡<br />

☛<br />

Therefore, the zeroes of x 2 – 3 are 3 and ✌ ☞ 3<br />

Now,<br />

sum of zeroes =<br />

3 3 0<br />

✂ ✄ ✄<br />

(Coefficient of x) ,<br />

2<br />

Coefficient of x<br />

✂<br />

3 Constant term<br />

✂<br />

✎✍ ✎ product of zeroes = 3 3 –3<br />

2<br />

✍<br />

1 Coefficient of x<br />

✂ ✄ ✄ ✄ ✞

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