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190 MATHEMATICS<br />

6. If A, B and C are interior angles of a triangle ABC, then show that<br />

= ✁<br />

✂ ✄ ✝<br />

☎ ✆<br />

sin<br />

B+C<br />

2<br />

A<br />

cos 2<br />

7. Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.<br />

8.5 Trigonometric Identities<br />

You may recall that an equation is called an identity<br />

when it is true for all values of the variables involved.<br />

Similarly, an equation involving trigonometric ratios<br />

of an angle is called a trigonometric identity, if it is<br />

true for all values of the angle(s) involved.<br />

In this section, we will prove one trigonometric<br />

identity, and use it further to prove other useful<br />

trigonometric identities.<br />

In ✞ ABC, right-angled at B (see Fig. 8.22), we have:<br />

Dividing each term of (1) by AC 2 , we get<br />

Fig. 8.22<br />

AB 2 + BC 2 =AC 2 (1)<br />

AB<br />

AC<br />

2 2<br />

BC<br />

✟ =<br />

AC<br />

2 2<br />

AC<br />

AC<br />

2<br />

2<br />

i.e.,<br />

2 2<br />

AB ✠ BC ✡ ✠ ✡<br />

☛ ☞ ✌ ☞ ✌<br />

AC AC<br />

✍ ✎ ✍ ✎<br />

=<br />

AC ✠ ✡<br />

☞ ✌<br />

AC<br />

✍<br />

✎<br />

2<br />

i.e., (cos A) 2 + (sin A) 2 =1<br />

i.e., cos 2 A + sin 2 A = 1 (2)<br />

This is true for all A such that 0° ✏ A ✏ 90°. So, this is a trigonometric identity.<br />

Let us now divide (1) by AB 2 . We get<br />

AB<br />

AB<br />

2 2<br />

BC<br />

✟ =<br />

AB<br />

2 2<br />

AC<br />

AB<br />

2<br />

2<br />

or,<br />

2 2<br />

AB ✠ BC ✡ ✠ ✡<br />

☛ ☞ ✌ ☞ ✌<br />

✍ ✎ ✍ ✎<br />

AB AB<br />

=<br />

AC ✠ ✡<br />

☞ ✌<br />

✍ AB<br />

✎<br />

i.e., 1 + tan 2 A = sec 2 A (3)<br />

2

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