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TRIANGLES 141<br />

11. In Fig. 6.40, E is a point on side CB<br />

produced of an isosceles triangle ABC<br />

with AB = AC. If AD BC and EF AC,<br />

prove that ✁ ABD ~ ✁ ECF.<br />

12. Sides AB and BC and median AD of a<br />

triangle ABC are respectively proportional<br />

to sides PQ and QR and median<br />

PM of ✁ PQR (see Fig. 6.41). Show that<br />

✁ ABC ~ ✁ PQR.<br />

Fig. 6.40<br />

13. D is a point on the side BC of a triangle<br />

ABC such that ✂ ADC = ✂ BAC. Show<br />

that CA 2 = CB.CD.<br />

14. Sides AB and AC and median AD of a<br />

triangle ABC are respectively<br />

proportional to sides PQ and PR and<br />

median PM of another triangle PQR.<br />

Show that ✁ ABC ~ ✁ PQR.<br />

15. A vertical pole of length 6 m casts a shadow 4 m long on the ground and at the same time<br />

a tower casts a shadow 28 m long. Find the height of the tower.<br />

16. If AD and PM are medians of triangles ABC and PQR, respectively where<br />

ABC ~ ✁ PQR, prove that AB<br />

✁<br />

PQ<br />

6.5 Areas of Similar Triangles<br />

✄<br />

AD<br />

PM<br />

You have learnt that in two similar triangles, the ratio of their corresponding sides is<br />

the same. Do you think there is any relationship between the ratio of their areas and<br />

the ratio of the corresponding sides? You know that area is measured in square units.<br />

So, you may expect that this ratio is the square of the ratio of their corresponding<br />

sides. This is indeed true and we shall prove it in the next theorem.<br />

☎<br />

Fig. 6.41<br />

Theorem 6.6 : The ratio of the areas<br />

of two similar triangles is equal to the<br />

square of the ratio of their<br />

corresponding sides.<br />

Proof : We are given two<br />

triangles ABC and PQR such that<br />

✆ ABC ~ ✆ PQR (see Fig. 6.42).<br />

Fig. 6.42

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