06.09.2018 Views

Understanding ASQ-CQA -Knowing The Ways

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If ũ and σ are estimated to be 98.94 μm and 1.03 μm, respectively, then<br />

C p = USL−LSL<br />

6σ<br />

= 106.00−94.00<br />

6 x 1.03<br />

= 1.94<br />

Index<br />

C pk = min[ USL−ũ , ũ−LSL ] = min[ 106.00−98.94 , 98.94−94.00<br />

3σ 3σ<br />

] = 1.6<br />

3 x 1.03 3 x 1.03<br />

C<br />

C pm =<br />

p<br />

√[1+( ũ−T<br />

σ )2 ] = 1.94<br />

√[1+( 98.94−100.00<br />

1.03 )2 ] = 1.35<br />

C pkm =<br />

C pk<br />

√[1+( ũ−T<br />

σ )2 ] = 1.6<br />

√[1+( 98.94−100.00<br />

1.03 )2 ] = 1.11<br />

<strong>The</strong> fact that the process is running off-center (about 1σ below its target) is reflected in<br />

the markedly different values for C p , C pk , C pm , and C pkm .<br />

C pk = min[ USL−ũ<br />

3σ , ũ−LSL<br />

3σ<br />

C pkm =<br />

] = min[ 106.00−98.94<br />

, 98.94−94.00<br />

3 x 1.03 3 x 1.03<br />

C pk<br />

√[1+( ũ−T<br />

σ )2 ] = 1.6<br />

√[1+( 98.94−100.00<br />

1.03 )2 ] = 1.11<br />

] = 1.6<br />

Charlie Chong/ Fion Zhang

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