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PR-6816IRE Essential Study Guides - Number Algebra Strategies

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Order of operation<br />

This is a rule for performing<br />

operations in expressions<br />

which have more than<br />

one operation, to ensure<br />

calculations are handled in<br />

the same way.<br />

Some calculators use an<br />

‘algebraic operating system’<br />

(AOS). This is used to follow<br />

the Rule of Order.<br />

Note:<br />

Multiplication and division are equally powerful operations,<br />

completed left to right in order as they appear, as are<br />

addition and subtraction.<br />

Patterns<br />

Patterns are repeated designs. Patterns occur in<br />

mathematics in many different ways and always follow a rule.<br />

Simple number patterns such as odd and even numbers are<br />

easily identifi ed. Here are some more complex patterns.<br />

Triangular numbers<br />

A triangular number is a number that can form the shape of a<br />

triangle.<br />

1 3 6 10<br />

May also be shown as<br />

Square numbers<br />

A square number is a number that can form the shape of a<br />

square.<br />

1 4<br />

9<br />

16<br />

Word problems as equations<br />

Sequences<br />

A sequence is a list of items. Any item in the list can be<br />

named by its position: first, second, third, fourth and so on.<br />

Some lists have patterns which define the position of each<br />

item. There are two kinds of sequences:<br />

Mathematical terms<br />

A word problem needs to be changed into an equation before it can be solved. ‘Key words’ and phrases are used in word<br />

problems to tell what type of operation (addition, subtraction, multiplication, division) should be used to solve the problem.<br />

Look at the<br />

table. It shows<br />

some common<br />

key words and<br />

phrases, together<br />

with the correct<br />

operation needed<br />

to solve the<br />

problem.<br />

Brackets ( )<br />

Index notation 2 3<br />

Multiplication x<br />

Division ÷<br />

Addition +<br />

Subtraction –<br />

Operation Key word Word problem Equation<br />

addition<br />

subtraction<br />

multiplication<br />

division<br />

<strong>Algebra</strong> facts<br />

sum The sum of my age and 15 equals 32. a + 15 = 32<br />

total<br />

The total of my age and my brother’s age, who is 11<br />

years old, is 24.<br />

a + 11 = 24<br />

more than<br />

Fifteen more than my age equals 32.<br />

(Can also be subtraction.)<br />

a + 15 = 32<br />

difference<br />

The difference between my age and my younger<br />

sister’s age, who is 9 years old, is 3 years.<br />

a – 9 = 3<br />

less than Twelve less than my age equals 49. a – 12 = 49<br />

product The product of my age and 21 is 252. a x 21 = 252<br />

times Five times my age is 60. 5 x a = 60<br />

group A number grouped into lots of 6 is 5. a ÷ 6 = 5<br />

shared<br />

equally<br />

A ‘finite’ sequence is a list made up of<br />

a limited number of items.<br />

For example,<br />

9, 0, 9, 0, 9, 0, 9, 0, 9, 0, 9, 0 is the sequence of 6<br />

alternating 9s and 0s.<br />

1, 3, 5, 7, 9, 11, 13, 15, 17, 19 is the sequence of the<br />

fi rst 10 odd numbers.<br />

An ‘infinite’ sequence is a list that<br />

continues without end.<br />

For example,<br />

d, e, f, d, e, f, d, e, f, d, e ... is the sequence of the<br />

letters d, e, f, repeating in this pattern forever.<br />

2, 4, 6, 8, 10, 12, 14, 16 ... is the sequence of even<br />

whole numbers. The 50th number in this sequence<br />

is 100.<br />

constant<br />

Adding, subtracting,<br />

multiplying or dividing by the<br />

same amount each time.<br />

equivalent<br />

Having the same value.<br />

equation<br />

A statement of equality<br />

between two expressions;<br />

e.g. 3 x 4 = 6 + 6<br />

132 lollies shared equally among a number of<br />

children is 11 lollies each.<br />

growing<br />

A pattern that is becoming<br />

larger.<br />

inequality<br />

Not having the same value.<br />

repeating<br />

The pattern uses the same<br />

symbols or pictures over<br />

and over.<br />

e.g. 3, 4, 3, 4, 3 …<br />

132 ÷ a = 11<br />

To make mental maths easier, use your known number facts first. Here are some<br />

ideas to help you …<br />

Counting on<br />

3 + 5 =<br />

(change the order) 5 + 3 =<br />

1 2 3<br />

5 6 7 8<br />

6 + 11 =<br />

(change the order) 11 + 6 =<br />

1 2 3 4 5 6<br />

11 12 13<br />

Doubling<br />

3 + 3 = 6<br />

5 + 5 = 10<br />

13 + 13 = 26<br />

Ask<br />

clarifying<br />

questions<br />

What is the<br />

question<br />

asking?<br />

Do I know<br />

anything about<br />

this topic?<br />

What does …<br />

really mean?<br />

What else<br />

could I find out<br />

about to help<br />

me answer the<br />

question?<br />

14 15 16 17<br />

Make<br />

assumptions<br />

Using my<br />

knowledge<br />

of … I can<br />

assume …<br />

I think …<br />

because I<br />

know …<br />

If I know …<br />

then it could<br />

be …<br />

Mental strategies<br />

25 + 25 = 50<br />

33 + 33 = 66<br />

70 + 70 = 140<br />

Estimate<br />

Can I use my<br />

judgment<br />

to make<br />

a suitable<br />

guess?<br />

What<br />

strategies<br />

could I use<br />

to estimate<br />

a solution to<br />

the problem?<br />

Near doubles<br />

5 + 6 =<br />

(5 + 5) + 1 =<br />

10 + 1 = 11<br />

Survey<br />

Can I find out<br />

information<br />

by asking a<br />

sample of<br />

people?<br />

Do I need to<br />

investigate<br />

similar data<br />

and compare<br />

it to my<br />

information?<br />

OR<br />

Bridging a ten<br />

Example 1<br />

9 + 6 =<br />

(9 + 1) + 5 =<br />

10 + 5 = 15<br />

Partitioning<br />

5 + 8 =<br />

(5 + 5) + 3 =<br />

10 + 3 = 13<br />

Problem-solving strategies<br />

Locate<br />

information<br />

Where<br />

could I find<br />

information to<br />

help me solve<br />

the problem?<br />

Internet<br />

Library<br />

Things I<br />

already know<br />

Ask an expert<br />

Friends<br />

Adults<br />

5 + 6 =<br />

(6 + 6) – 1 =<br />

12 – 1 = 11<br />

Example 2<br />

www .prim-ed.com<br />

7 + 5 =<br />

(7 + 3) + 2 =<br />

10 + 2 = 12<br />

Present<br />

findings<br />

What is the<br />

best way to<br />

show what I<br />

have found?<br />

Diagrams<br />

Tables<br />

Graphs<br />

Calculations<br />

Explanations<br />

It is important to check your work to make sure answers to problems are<br />

correct and sensible. Checking your work can be done in many ways; some<br />

are shown below.<br />

Question your<br />

answer<br />

Ask yourself if the answer sounds<br />

right. A question you might ask<br />

yourself is …<br />

‘Is the answer way too big or way<br />

too small?’<br />

If you think the answer does<br />

not seem right, try some of the<br />

following checking strategies.<br />

Addition Subtraction Multiplication<br />

odd + odd = even<br />

odd + even = odd<br />

even + even = even<br />

Consider the size of the answer …<br />

When you read a question, do you ever consider how big the answer will be? Think<br />

about if the answer will be in tens, hundreds, thousands … or bigger! There is a<br />

pattern that can help alert you to potential errors.<br />

Addition<br />

Multiplication<br />

<strong>Number</strong> of digits<br />

Answer likely to be in the …<br />

1 digit + 1 digit units or tens<br />

2 digits + 1 digit tens or hundreds<br />

2 digits + 2 digits tens or hundreds<br />

3 digits + 1 digit hundreds or thousands<br />

3 digits + 2 digits hundreds or thousands<br />

3 digits + 3 digits hundreds or thousands<br />

1 digit x 1 digit units or tens<br />

2 digits x 1 digit tens or hundreds<br />

2 digits x 2 digits hundreds or thousands<br />

3 digits x 1 digit hundreds or thousands<br />

3 digits x 2 digits thousands or ten thousands<br />

3 digits x 3 digits ten thousands or hundred thousands<br />

Estimating<br />

Estimating gives you an answer that is<br />

close to the exact answer. It is usually<br />

found by rounding or by using judgment<br />

to make a ‘best guess’.<br />

Front-end rounding<br />

1. Look at the left-most digit in the<br />

number.<br />

2. Consider the place value of the digit.<br />

For example,<br />

3 2 1 5<br />

6 9 1 0<br />

+ 4 3 4 2<br />

3 + 6 + 4 = 13<br />

Viewing Sample<br />

www .prim-ed.com<br />

So the estimate would be 13 000.<br />

Checking strategies<br />

Odd and even numbers<br />

Odd and even numbers follow a pattern. Once you are aware of the pattern, all<br />

you need to do is look at the units digits of the numbers in the problem, and the<br />

answer to determine whether the answer is defi nitely wrong or possibly correct.<br />

Think about the context of the<br />

numbers before rounding.<br />

For example,<br />

When calculating the cost of groceries,<br />

it is probably better to overestimate so<br />

you do not run short of money.<br />

When calculating, you<br />

should:<br />

1. Estimate<br />

2. Calculate<br />

3. Evaluate (How close was your<br />

estimate? Could you improve on<br />

your technique?)<br />

odd – odd = even<br />

odd – even = odd<br />

even – odd = odd<br />

even – even = even<br />

odd x odd = odd<br />

odd x even = even<br />

even x even = even<br />

Divisibility<br />

rules<br />

It is often helpful to know when one<br />

number may be divided into another<br />

without leaving a remainder.<br />

2<br />

3<br />

4<br />

5<br />

6<br />

9<br />

10<br />

11<br />

12<br />

25<br />

100<br />

Any even number;<br />

e.g. 2, 4, 6, 8 or 0<br />

Sum of all digits = multiple of 3;<br />

e.g. 8652 = 8 + 6 + 5 + 2 = 21;<br />

2 + 1 = 3<br />

Last two digits divisible by 4;<br />

e.g. 23 632, 45 656, 13 988<br />

Any number ending in 0 or 5;<br />

e.g. 20, 45, 670, 9845<br />

Any number divisible by 2 and 3;<br />

e.g. 54, 972, 2196<br />

Sum of all digits = multiple of 9;<br />

e.g. 72 567 = 7 + 2 + 5 + 6 + 7<br />

= 27; 2 + 7 = 9<br />

Any number ending in 0;<br />

e.g. 10, 200, 7680, 98 450<br />

Alternate digit sums differ by a<br />

multiple of 11 or 0;<br />

e.g. 76 285 = 7 + 2 + 5 = 14<br />

6 + 8 = 14; 14 – 14 = 0<br />

Any number divisible by 3 and 4;<br />

e.g. 180, 720, 3600<br />

Last two digits divisible by 25;<br />

e.g. 6475, 8950<br />

Last two digits are 00;<br />

e.g. 67 400, 589 780 300<br />

Repeat the calculation:<br />

•<br />

carefully, in exactly the same<br />

way.<br />

• using the inverse operation.<br />

• using a different method.<br />

Maths<br />

No part of this publication may be reproduced in any form or<br />

by any means, electronic or mechanical, including photocopying<br />

or recording, or by any information storage and retrieval<br />

system, without written permission from the publisher.<br />

<strong>PR</strong>–6816<br />

Copyright Information<br />

ISBN 1-84654-025-9<br />

9!BMFCIA:TSOQTV!<br />

6816RE maths 1.indd 2<br />

8/12/05 11:01:07 AM

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