J17
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x -5 -4 -3 -2 -1 0 1 2 3 4 5<br />
y -25 -16 -9 -4 -1 0 -1 -4 -9 -16 -25<br />
Note:<br />
(a) The maximum value of the curve is 0 at the origin.<br />
(b) The curve is symmetrical about the y-axis.<br />
Example<br />
Draw the graph of y = x 2 – 3x + 2, for values of x between -1 and +4.<br />
Solution<br />
Make a table of values of x and y:<br />
x -1 0 1 1.5 2 3 4<br />
x 2 1 0 1 2.25 4 9 16<br />
-3x 3 0 -3 -4.5 -6 -9 -12<br />
+2 +2 +2 +2 +2 +2 +2 +2<br />
y 6 2 0 -0.25 0 2 6<br />
Since both x = 1 and x = 2 give y = 0, it is advisable to take a value of x between 1 and<br />
2, i.e. 1.5.<br />
Note that the maximum value of the function is -0.25.