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Example<br />

Solve the equation 2x 2 + 7x = 2<br />

Solution<br />

Writing the equation in the general form ax 2 + bx + c = 0 we get<br />

2x 2 + 7x - 2 = 0<br />

Hence a= 2, b = 7, c = -2<br />

Substitute these values in<br />

b<br />

( b<br />

2 4ac)<br />

x<br />

2a<br />

7 47 (4<br />

2 2)<br />

7 ± 65<br />

=<br />

=<br />

2<br />

2<br />

4<br />

Hence x = 0.27 or x = -3.77 (2 d.p)<br />

Example<br />

Solve: 2x(x – 1) = (x+ 1) 2 – 5<br />

Solution<br />

First we re-arrange the terms in the equation as follows.<br />

2x(x – 1) = (x + 1) 2 – 5<br />

⇔ 2x 2 – 2x = x 2 + 2x + 1 – 5<br />

2x 2 – 2x – x 2 – 2x – 1 + 5 = 0<br />

x 2 – 4x + 4 = 0<br />

(x – 2)(x – 2) = 0<br />

x = 2<br />

In this example the quadratic equation has a repeated root<br />

Exercise<br />

Solve the following, giving answers to two decimal places where necessary:<br />

1. 2x 2 + 11x + 5 = 0 2. 3x 2 + 11x + 6 = 0<br />

3. 6x 2 + 7x + 2= 0 4. 3x 2 – 10x + 3 = 0<br />

5. 5x 2 – 7x + 2 = 0 6. 6x 2 – 11x + 3 = 0<br />

7. 2x 2 + 6x + 3 = 0 8. x 2 + 4x + 1 = 0<br />

9. 5x 2 – 5x + 1 = 0 10. x 2 – 7x + 2 = 0<br />

11 2x 2 + 5x – 1 = 0 12. 3x 2 + x – 3 = 0<br />

13. 3x 2 + 8x – 6 = 0 14. 3x 2 – 7x – 20 = 0<br />

15. 2x 2 – 7x – 15 = 0 16. x 2 – 3x – 2 = 0<br />

17. 2x 2 + 6x – 1 = 0 18. 6x 2 - 11x – 7 = 0<br />

19. 3x 2 + 25x + 8 = 0 20. 3y 2 – 2y – 5 = 0

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