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Sec. 6–8 Matched Filters 473<br />

r(t)=s(t)+n(t)<br />

Delay<br />

T<br />

Delay<br />

T<br />

Delay<br />

T<br />

Delay<br />

T<br />

a 1 a 2 a 3 a N<br />

<br />

r 0 (t)=s 0 (t)+n 0 (t)<br />

Figure 6–20<br />

Transversal matched filter.<br />

or<br />

(6–170)<br />

where R n (t) is the autocorrelation of the input noise. Thus, the output-peak-signal-to-averagenoise-power<br />

ratio is<br />

N<br />

2<br />

s 2 c<br />

0 (t 0 ) a a k s(t 0 - (k - 1)T) d<br />

(6–171)<br />

n 2 0 (t) = k = 1<br />

N<br />

a a k a l R n (kT - lT)<br />

We can find the a k ’s that maximize this ratio by using Lagrange’s method of maximizing the<br />

numerator while constraining the denominator to be a constant [Olmsted, 1961, p. 518].<br />

Consequently, we need to maximize the function<br />

(6–172)<br />

where l is the Lagrange multiplier. The maximum occurs when 0M/0a i = 0 for all the i = 1,<br />

2,...,N. Thus,<br />

0M<br />

0a i<br />

M(a 1 , a 2 , . . . , a N ) = c a<br />

N<br />

= 0 = 2c a<br />

N<br />

n 2 N<br />

0 (t) = a<br />

k =1<br />

a k s(t 0 - (k - 1)T) d s(t 0 - (i - 1)T)<br />

N<br />

- 2l a a k R n (kT - iT)<br />

k=1<br />

N<br />

a<br />

k = 1 l = 1<br />

N<br />

a<br />

k = 1 l = 1<br />

k = 1<br />

-l a<br />

N<br />

a k a l R n (kT - lT)<br />

2<br />

a k s(t 0 - (k - 1)T) d<br />

N<br />

a<br />

k = 1 l = 1<br />

a k a l R n (kT - lT)<br />

(6–173)

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