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Sec. 6–7 Bandpass Processes 463 f R (R) 0.6 f R (R)= (R/Í 2 )eR 2 /2Í 2 , R ≥ 0 0 , R < 0 0.4 where Í=1 0.2 (a) PDF for the Envelope R f¨ (¨) 1 2∏ 2∏ ¨ (b) PDF for the Phase Figure 6–14 PDF for the envelope and phase of a Gaussian process. This is called a uniform PDF. Sketches of these PDFs are shown in Fig. 6–14. The random variables R = R(t 1 ) and u = u(t 1 ) are independent, since f R (R, u) = f R (R) f(u). However, R(t) and u(t) are not independent random processes because the random variables R = R(t 1 ) and u = u(t 1 + t) are not independent for all values of t. To verify this statement, a fourdimensional transformation problem consisting of transforming the random variables (x(t 1 ), x(t 2 ), y(t 1 ), y(t 2 )) into (R(t 1 ), R(t 2 ), u (t 1 ), u (t 2 )) needs to be worked out, where t 2 - t 1 = t (Davenport and Root, 1958). The evaluation of the autocorrelation function for the envelope R(t) generally requires that the two-dimensional density function of R(t) be known, since R R (t) = R(t)R(t + t) . However, to obtain this joint density function for R(t), the four-dimensional density function of (R(t 1 ), R(t 2 ), u(t 1 ), u(t 2 )) must first be obtained by a four-dimensional transformation, as discussed in the preceding paragraph. A similar problem is worked to evaluate the autocorrelation function for the phase u(t). These difficulties in evaluating the autocorrelation function for R(t) and u(t) arise because they are nonlinear functions of v(t). The PSDs for R(t) and u(t) are obtained by taking the Fourier transform of the autocorrelation function.
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Sec. 6–7 Bandpass Processes 463<br />
f R (R)<br />
0.6<br />
f R (R)=<br />
(R/Í 2 )eR 2 /2Í 2 , R ≥ 0<br />
0 , R < 0<br />
0.4<br />
where Í=1<br />
0.2<br />
(a) PDF for the Envelope<br />
R<br />
f¨ (¨)<br />
1<br />
2∏<br />
2∏<br />
¨<br />
(b) PDF for the Phase<br />
Figure 6–14 PDF for the envelope and phase of a Gaussian process.<br />
This is called a uniform PDF. Sketches of these PDFs are shown in Fig. 6–14.<br />
The random variables R = R(t 1 ) and u = u(t 1 ) are independent, since f R (R, u) = f R (R) f(u).<br />
However, R(t) and u(t) are not independent random processes because the random variables<br />
R = R(t 1 ) and u = u(t 1 + t) are not independent for all values of t. To verify this statement, a fourdimensional<br />
transformation problem consisting of transforming the random variables (x(t 1 ), x(t 2 ),<br />
y(t 1 ), y(t 2 )) into (R(t 1 ), R(t 2 ), u (t 1 ), u (t 2 )) needs to be worked out, where t 2 - t 1 = t (Davenport<br />
and Root, 1958).<br />
The evaluation of the autocorrelation function for the envelope R(t) generally requires<br />
that the two-dimensional density function of R(t) be known, since R R (t) = R(t)R(t + t) .<br />
However, to obtain this joint density function for R(t), the four-dimensional density function<br />
of (R(t 1 ), R(t 2 ), u(t 1 ), u(t 2 )) must first be obtained by a four-dimensional transformation, as<br />
discussed in the preceding paragraph. A similar problem is worked to evaluate the autocorrelation<br />
function for the phase u(t). These difficulties in evaluating the autocorrelation function<br />
for R(t) and u(t) arise because they are nonlinear functions of v(t). The PSDs for R(t) and u(t)<br />
are obtained by taking the Fourier transform of the autocorrelation function.