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Sec. 6–7 Bandpass Processes 459<br />

Proofs of Some Properties<br />

Giving proofs for all 17 properties listed previously would be a long task. We therefore<br />

present detailed proofs only for some of them. Proofs that involve similar mathematics will be<br />

left to the reader as exercise problems.<br />

Properties 1 through 3 have already been proven in the discussion preceding<br />

Eq. (6–131). Property 4 follows readily from property 3 by taking the Fourier transform of<br />

Eq. (6–133c). The mathematics is identical to that used in obtaining Eq. (4–25). Property<br />

5 also follows directly from property 3. Property 6 will be shown subsequently. Property 7<br />

follows from properties 3 and 8. As we will see later, properties 8 through 11 follow from<br />

properties 12 and 13.<br />

Properties 6 and 12 are obtained with the aid of Fig. 6–11. That is, as shown by<br />

Eq. (4–77) in Sec. 4–13, x(t) and y(t) can be recovered by using product detectors. Thus,<br />

x(t) = [2v(t) cos(v c t + u 0 )] * h(t)<br />

(6–139)<br />

and<br />

y(t) = -[2v(t) sin(v c t + u 0 )] * h(t)<br />

(6–140)<br />

where h(t) is the impulse response of an ideal LPF that is bandlimited to B 0 hertz and u 0 is an<br />

independent random variable that is uniformly distributed over (0, 2p) and corresponds to<br />

the random start-up phase of a phase-incoherent receiver oscillator. Property 6 follows<br />

from Eq. (6–139) by taking the ensemble average since cos (v c t + u 0 ) = 0 and<br />

sin (v c t + u 0 ) = 0. Property 12, which is the PSD for x(t), can be evaluated by first evaluating<br />

the autocorrelation for w 1 (t) of Fig. 6–11:<br />

w 1 (t) = 2v(t) cos(v c t + u 0 )<br />

R w1 (t) = w 1 (t)w 1 (t + t)<br />

= 4v(t)v(t + t) cos(v c t + u 0 ) cos(v c (t + t) + u 0 )<br />

But u 0 is an independent random variable; hence, using a trigonometric identity, we have<br />

R w1 (t) = 4v(t)v(t + t) C 1 2 cos v ct + 1 2 cos(2v ct) + v c t + 2u 0 )D<br />

However,<br />

cos(2v c t + v c t + 2u 0 ) = 0, so<br />

R w1 (t) = 2R v (t) cos v c t<br />

(6–141)<br />

The PSD of w 1 (t) is obtained by taking the Fourier transform of Eq. (6–141).<br />

or<br />

w1 (f) = 2 v (f) * C 1 2 d(f - f c) + 1 2 d(f + f c)D<br />

w1 (f) = v (f - f c ) + v (f + f c )<br />

Finally, the PSD of x(t) is<br />

x (f) = ƒ H(f) ƒ 2 w1 (f)

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