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Sec. 6–2 Power Spectral Density 435 where Substituting this expression for R(k) into Eq. (6–70b) and using R(-k) = R(k), we get x (f) = |F(f)|2 q 2 cs T a a r(k)e -jkvT q s 2 + m a a e -jkvT s d s Thus, for the general case of correlated data, the PSD of the digital signal is where x ( f) = s 2 a D|F(f)| 2 p (f) + (m a D) 2 Continuous spectrum r (f) r(k) = [a ' na ' n + k] (6–70e) (6–70f) is a spectral weight function obtained from the Fourier transform of the normalized autocorrelation impulse train q a k = -q k = -q q a k = -q r(k)e -j2pkfT s r(k)d(t - kT s ) This demonstrates that the PSD of the digital signal consists of a continuous spectrum that depends on the pulse-shape spectrum F( f ) and the data correlation. Furthermore, if m a 0 and F(nD) 0, the PSD will also contain spectral lines (delta functions) spaced at harmonics of the baud rate D. Examples of the application of these results are given in Sec. 3–5, where the PSD for unipolar RZ, bipolar, and Manchester line codes are evaluated. (See Fig. 3–16 for a plot of the PSDs for these codes.) Examples of bandpass digital signaling, such as OOK, BPSK, QPSK, MPSK, and QAM, are given in Sections 5–9 and 5–10. q a ⎧ ⎪⎪⎪⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎪⎪⎩ ⎧ ⎪⎪⎪⎪⎨⎪⎪⎪⎪⎩ n = - q k = -q |F(nD)| 2 d (f - nD) Discrete spectrum Example 6–5 PSD FOR A BIPOLAR NRZ LINE CODE USING THE DATA AUTOCORRELATION Using Eq. (6–70b) and referring to Fig. (3–15e), evaluate and plot the PSD for a bipolar NRZ line code with A = 1.414 and R = 1. Also, evaluate and plot the PSD for a bipolar RZ line code with A = 2 and R = 1. (The A’s are selected so that the NRZ and RZ line codes have the same average energy per bit, E b .) See Example6_05.m for the solution. Compare these results with Fig. 3–16d. White-Noise Processes DEFINITION. A random process x(t) is said to be a white-noise process if the PSD is constant over all frequencies; that is, x (f) = N 0 2 (6–71)
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Sec. 6–2 Power Spectral Density 435<br />
where<br />
Substituting this expression for R(k) into Eq. (6–70b) and using R(-k) = R(k), we get<br />
x (f) = |F(f)|2 q<br />
2<br />
cs<br />
T a a r(k)e -jkvT q<br />
s 2<br />
+ m a a e -jkvT s<br />
d<br />
s<br />
Thus, for the general case of correlated data, the PSD of the digital signal is<br />
where<br />
x ( f) = s 2 a D|F(f)| 2 p (f) + (m a D) 2<br />
Continuous spectrum<br />
r (f)<br />
r(k) = [a ' na ' n + k]<br />
(6–70e)<br />
(6–70f)<br />
is a spectral weight function obtained from the Fourier transform of the normalized autocorrelation<br />
impulse train<br />
q<br />
a<br />
k = -q<br />
k = -q<br />
q<br />
a<br />
k = -q<br />
r(k)e -j2pkfT s<br />
r(k)d(t - kT s )<br />
This demonstrates that the PSD of the digital signal consists of a continuous spectrum that<br />
depends on the pulse-shape spectrum F( f ) and the data correlation. Furthermore, if m a 0<br />
and F(nD) 0, the PSD will also contain spectral lines (delta functions) spaced at harmonics<br />
of the baud rate D.<br />
Examples of the application of these results are given in Sec. 3–5, where the PSD for<br />
unipolar RZ, bipolar, and Manchester line codes are evaluated. (See Fig. 3–16 for a plot of the<br />
PSDs for these codes.) Examples of bandpass digital signaling, such as OOK, BPSK, QPSK,<br />
MPSK, and QAM, are given in Sections 5–9 and 5–10.<br />
q<br />
a<br />
⎧ ⎪⎪⎪⎪⎪⎪⎪⎪⎨⎪⎪⎪⎪⎪⎪⎪⎩<br />
⎧ ⎪⎪⎪⎪⎨⎪⎪⎪⎪⎩<br />
n = - q<br />
k = -q<br />
|F(nD)| 2 d (f - nD)<br />
Discrete spectrum<br />
Example 6–5 PSD FOR A BIPOLAR NRZ LINE CODE USING<br />
THE DATA AUTOCORRELATION<br />
Using Eq. (6–70b) and referring to Fig. (3–15e), evaluate and plot the PSD for a bipolar NRZ line<br />
code with A = 1.414 and R = 1. Also, evaluate and plot the PSD for a bipolar RZ line code with<br />
A = 2 and R = 1. (The A’s are selected so that the NRZ and RZ line codes have the same average<br />
energy per bit, E b .) See Example6_05.m for the solution. Compare these results with Fig. 3–16d.<br />
White-Noise Processes<br />
DEFINITION. A random process x(t) is said to be a white-noise process if the PSD is<br />
constant over all frequencies; that is,<br />
x (f) = N 0<br />
2<br />
(6–71)