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316<br />

AM, FM, and Digital Modulated Systems Chap. 5<br />

which is a distorted AM signal. The bandwidth of this signal is much wider than that of the<br />

undistorted AM signal, as is easily demonstrated by spectral analysis. This is the overmodulated<br />

condition that the FCC does not allow. An AM transmitter that uses pulse width modulation is<br />

an example of a circuit that acts as a two-quadrant multiplier (see Fig. 5–2 and the discussion of<br />

this figure that follows Example 5–3). This produces the product A c [1 + m(t)] cos v c t, provided<br />

that m(t) Ú -1, but produces no output when m(t) 6-1.<br />

Example 5–2 AM SIGNAL WITH 150% MODULATION<br />

Let an AM signal with a carrier frequency of 10 Hz be modulated with a sinusoidal signal<br />

having a frequency of 1 Hz and 150% modulation. Assume that the AM transmitter uses a<br />

two-quadrant multiplier. Plot the AM signal at the transmitter output. See Example5_02.m for<br />

the solution.<br />

If the percentage of negative modulation is less than 100%, an envelope detector<br />

may be used to recover the modulation without distortion, since the envelope, |g(t)| =<br />

|A c [1 + m(t)]|, is identical to A c [1 + m(t)]. If the percentage of negative modulation is over<br />

100%, undistorted modulation can still be recovered provided that the proper type of<br />

detector—a product detector—is used. This is seen from Eq. (4–76) with u 0 = 0.<br />

Furthermore, the product detector may be used for any percentage of modulation. In<br />

Chapter 7, we will see that a product detector is superior to an envelope detector when the<br />

input signal-to-noise ratio is small.<br />

From Eq. (4–17), the normalized average power of the AM signal is<br />

8s 2 (t)9 = 1 2 8|g(t)|2 9 = 1 2 A c 2 8[1 + m(t)] 2 9<br />

= 1 2 A c 2 81 + 2m(t) + m 2 (t)9<br />

= 1 2 A c 2 + A c 2 8m(t)9 + 1 2 A c 2 8m 2 (t)9<br />

(5–8)<br />

If the modulation contains no DC level, then 8m(t) 9 = 0 and the normalized power of the AM<br />

signal is<br />

8s 2 (t)9 = 1 2 A c 2<br />

⎧<br />

⎨⎩<br />

⎧<br />

⎪⎨⎪⎩<br />

discrete<br />

carrier power<br />

+ 1 2 A c 2 8m 2 (t)9<br />

sideband power<br />

(5–9)<br />

DEFINITION. The modulation efficiency is the percentage of the total power of the<br />

modulated signal that conveys information.<br />

In AM signaling, only the sideband components convey information, so the modulation<br />

efficiency is<br />

E =<br />

8m 2 (t)9<br />

1 + 8m 2 (t)9 * 100%<br />

(5–10)

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