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Sec. 4–11 Mixers, Up Converters, and Down Converters 271<br />

+<br />

+<br />

v in<br />

RF<br />

port<br />

LO<br />

port<br />

v LO<br />

Local<br />

oscillator<br />

–<br />

–<br />

IF port<br />

–<br />

v 1 (t)<br />

+<br />

(a) A Double-Balanced Mixer Circuit<br />

Load<br />

+<br />

–<br />

v in (t)<br />

v LO (t)<br />

v in (t)<br />

v LO (t)<br />

–<br />

+<br />

v 1 (t)<br />

(b) Equivalent Circuit When v LO (t) Is Positive<br />

v 1 (t)<br />

(c) Equivalent Circuit When v LO (t) Is Negative<br />

+1<br />

s(t)<br />

–1<br />

t<br />

(d) Switching Waveform Due to the Local Oscillator Signal<br />

T 0<br />

Figure 4–11<br />

Analysis of a double-balanced mixer circuit.<br />

signal. This circuit thus acts as a time-varying linear circuit (with respect to the RF input<br />

port), and its analysis is very similar to that used for the analog-switch mixer of Fig. 4–10.<br />

During the portion of the cycle when v LO (t) has a positive voltage, the output voltage is proportional<br />

to +v in (t), as seen from the equivalent circuit shown in Fig. 4–11b. When v LO (t) is<br />

negative, the output voltage is proportional to -v in (t), as seen from the equivalent circuit<br />

shown in Fig. 4–11c. Thus, the output of this double-balanced mixer is<br />

v 1 (t) = Kv in (t) s(t)<br />

(4–69)

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