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270<br />

Bandpass Signaling Principles and Circuits Chap. 4<br />

where s(t) is a unipolar switching square wave that has unity peak amplitude. (This is analogous<br />

to the PAM with natural sampling that was studied in Chapter 3.) Using the Fourier series for a<br />

rectangular wave, we find that Eq. (4–65) becomes<br />

v 1 (t) = v in (t)c 1 q<br />

2 + 2 sin (np/2)<br />

a<br />

n=1 np<br />

cos nv 0 t d<br />

(4–66)<br />

The multiplying action is obtained from the n = 1 term, which is<br />

2<br />

p v in(t) cos v 0 t<br />

(4–67)<br />

This term would generate up- and down-conversion signals at f c + f 0 and f c - f 0 if v in (t) were<br />

a bandpass signal with a nonzero spectrum in the vicinity of f = f c . However, Eq. (4–66) shows<br />

that other frequency bands are also present in the output signal, namely, at frequencies f =<br />

1<br />

|f c ± nf 0 |, n = 3, 5, 7, ... and, in addition, there is the feed-through term 2 v in(t) appearing at the<br />

output. Of course, a filter may be used to pass either the up- or down-conversion component<br />

appearing in Eq. (4–66).<br />

Mixers are often classified as being unbalanced, single balanced, or double balanced.<br />

That is, in general, we obtain<br />

v 1 (t) = C 1 v in (t) + C 2 v 0 (t) + C 3 v in (t)v 0 (t) + other terms<br />

(4–68)<br />

at the output of mixer circuits. When C 1 and C 2 are not zero, the mixer is said to be<br />

unbalanced, since v in (t) and v 0 (t) feed through to the output. An unbalanced mixer was illustrated<br />

in Fig. 4–9, in which a nonlinear device was used to obtain mixing action. In the<br />

Taylor’s expansion of the nonlinear device output-to-input characteristics, the linear term<br />

would provide feed-through of both v in (t) and v 0 (t). A single-balanced mixer has feedthrough<br />

for only one of the inputs; that is, either C 1 or C 2 of Eq. (4–68) is zero. An example<br />

of a single-balanced mixer is given in Fig. 4–10, which uses sampling to obtain mixer action.<br />

In this example, Eq. (4–66) demonstrates that v 0 (t) is balanced out (i.e., C 2 = 0) and v in (t)<br />

feeds through with a gain of C 1 = 1 2 . A double-balanced mixer has no feed-through from<br />

either input; that is, both C 1 and C 2 of Eq. (4–68) are zero. One kind of double-balanced mixer<br />

is discussed in the next paragraph.<br />

Figure 4–11a shows the circuit for a double-balanced mixer. This circuit is popular<br />

because it is relatively inexpensive and has excellent performance. The third-order IMD is<br />

typically down at least 50 dB compared with the desired output components. This mixer is<br />

usually designed for source and load impedances of 50 Ω and has broadband input and output<br />

ports. The RF [i.e., v in (t)] port and the LO (local oscillator) port are often usable over a<br />

frequency range of 1,000:1, say, 1 to 1,000 MHz; and the IF (intermediate frequency) output<br />

port, v 1 (t), is typically usable from DC to 600 MHz. The transformers are made by using<br />

small toroidal cores, and the diodes are matched hot carrier diodes. The input signal level at<br />

the RF port is relatively small, usually less than -5 dBm, and the local oscillator level at the<br />

LO port is relatively large, say, +5 dBm. The LO signal is large, and, in effect, turns the diodes<br />

on and off so that the diodes will act as switches. The LO provides the switching control

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