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Sec. 3–2 Pulse Amplitude Modulation 139<br />

where t … T s = 1f s and f s Ú 2B.<br />

THEOREM.<br />

The spectrum for a flat-top PAM signal is<br />

where<br />

W s (f) = 1 q<br />

H(f)<br />

T a W(f - kf s )<br />

s k =-q<br />

H(f) = [h(t)] = t a<br />

sin ptf<br />

ptf<br />

b<br />

(3–10)<br />

(3–11)<br />

This type of PAM signal is said to consist of instantaneous samples, since w(t) is<br />

sampled at t kT s and the sample values w(kT s ) determine the amplitude of the flat-top<br />

rectangular pulses, as demonstrated in Fig. 3–5c. The flat-top PAM signal could be generated<br />

by using a sample-and-hold type of electronic circuit.<br />

Another pulse shape, rather than the rectangular shape, could be used in Eq. (3–8), but<br />

in this case the resulting PAM waveform would not be flat topped. Note that if the h(t) is of<br />

the (sin x)x type with overlapping pulses, then Eq. (3–8) becomes identical to the sampling<br />

theorem of Eq. (2–158), and this sampled signal becomes identical to the original unsampled<br />

analog waveform, w(t).<br />

PROOF. The spectrum for flat-top PAM can be obtained by taking the Fourier transform<br />

of Eq. (3–8). First we rewrite that equation, using a more convenient form involving the<br />

convolution operation:<br />

w s (t) = ak<br />

w(kT s )h(t) * d(t - kT s )<br />

Hence,<br />

= h(t) * ak<br />

w(kT s )d(t - kT s )<br />

The spectrum is<br />

w s (t) = h(t) * cw(t) a<br />

k<br />

d(t - kT s )d<br />

W s (f) = H(f)cW(f) * ak<br />

e -j2pfkT s<br />

d<br />

(3–12)<br />

But the sum of the exponential functions is equivalent to a Fourier series expansion (in the<br />

frequency domain), where the periodic function is an impulse train. That is,<br />

1<br />

T s<br />

a k<br />

d(f - kf s ) = 1 T s<br />

q<br />

a<br />

n =-q<br />

c n e j(2pnT s)f ,<br />

(3–13a)

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