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Problems 119<br />

Sinusoidal<br />

current<br />

source<br />

I rms = 0.5 mA<br />

Amplifier<br />

50 <br />

V rms = 10 V<br />

Figure P2–10<br />

★ 2–10 An amplifier is connected to a 50-Ω load and driven by a sinusoidal current source, as shown in<br />

Fig. P2–10. The output resistance of the amplifier is 10 Ω and the input resistance is 2 kΩ.<br />

Evaluate the true decibel gain of this circuit.<br />

★ 2–11 The voltage (RMS) across the 300-Ω antenna input terminals of an FM receiver is 3.5 µV.<br />

(a) Find the input power (watts).<br />

(b) Evaluate the input power as measured in decibels below 1 mW (dBm).<br />

(c) What would be the input voltage (in microvolts) for the same input power if the input resistance<br />

were 75 Ω instead of 300 Ω?<br />

2–12 A 103.5 MHz FM signal from an antenna is applied to a FM receiver via a coaxial cable. This signal<br />

has a power level of -100 dBm at this receiver’s 75-Ω antenna input. What is the rms voltage<br />

of this FM signal at the antenna input?<br />

2–13 What is the value for the phasor that corresponds to the voltage waveform v(t) = 15 sin (v 0 t -30°),<br />

where v 0 = 2000p?<br />

2–14 A signal is w(t) = 6 sin (100pt - 40°) + 4 cos (100pt). Find the corresponding phasor.<br />

★ 2–15 Evaluate the Fourier transform of<br />

2–16 Find the spectrum for the waveform w(t) = e -p(t/T)2 in terms of the parameter T. What can we<br />

say about the width of w(t) and W(f) as T increases?<br />

2–17 Using the convolution property, find the spectrum for<br />

★ 2–18 Find the spectrum (Fourier transform) of the triangle waveform<br />

in terms of A and T 0 .<br />

2–19 Find the spectrum for the waveform shown in Fig. P2–19.<br />

2–20 If w(t) has the Fourier transform<br />

W(f) =<br />

find X( f ) for the following waveforms:<br />

(a) x(t) = w(2t + 2).<br />

(b) x(t) = e -jt w(t - 1).<br />

w(t) = e e-at , t Ú 1<br />

0, t 6 1<br />

w(t) = sin 2pf 1 t cos 2pf 2 t<br />

s(t) = e At, 0 6 t 6 T 0<br />

0, t elsewhere<br />

j2pf<br />

1 + j2pf

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