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Sec. 2–2 Fourier Transform and Spectra 59<br />

In terms of quadrature notation, Eq. (2–57) becomes<br />

V(f) = [T Sa(pfT) cos(pfT)] + j[-T Sa(pfT) sin(pfT)<br />

(2–58)<br />

w<br />

w<br />

X(f)<br />

Examining Eq. (2–57), we find that the magnitude spectrum is<br />

and the phase spectrum is<br />

sin pfT<br />

|V(f)| = T `<br />

pfT<br />

0,<br />

u(f) = le -jp/T + lSa(pfT) = -pfT+ d<br />

p,<br />

Y(f)<br />

n<br />

T 6 ƒfƒ 6 n + 1<br />

(2–59)<br />

T , n even<br />

(2–60)<br />

n<br />

T 6 ƒ f ƒ 6 n + 1<br />

T , n odd<br />

The rectangular pulse is one of the most important and popular pulse shapes, because it<br />

is convenient to represent binary one and binary zero data by using rectangular pulses. For<br />

example, TTL logic circuits use 5-volt rectangular pulses to represent binary ones and 0 volts<br />

to represent binary zeros. This is shown in Fig. 3–15a, where A = 5. Other examples of<br />

rectangular pulse encoding are also shown in Fig. 3–15.<br />

The null bandwidth for rectangular pulse digital signaling is obtained from Eq. (2–55)<br />

or Eq. (2–59). That is, if the pulse width of a digital signal is T seconds, then the bandwidth<br />

(i.e., the width of the frequency band where the spectral magnitude is not small) is approximately<br />

1/T Hz. A complete discussion of signal bandwidth is involved, and this is postponed<br />

until Sec. 2–9.<br />

Example 2–7 SPECTRUM OF A TRIANGULAR PULSE<br />

The spectrum of a triangular pulse can be obtained by direct evaluation of the FT integral using<br />

equations for the piecewise linear lines of the triangle shown in Fig. 2–6c. Another approach,<br />

which allows us to obtain the FT quickly, is to first compute the FT for the second derivative of<br />

the triangle. We will take the latter approach to demonstrate this technique. Let<br />

Then<br />

w(t) =(t/T)<br />

dw(t)<br />

dt<br />

= 1 T u(t + T) - 2 T u(t) + 1 u(t - T)<br />

T<br />

and<br />

d 2 w(t)<br />

dt 2 = 1 T d(t + T) - 2 T d(t) + 1 d(t - T)<br />

T

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