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B–8 Functional Transformations of Random Variables 707<br />

where B 0. For y 0, M = 1; and for y 0, M = 0. However, if y = 0, there are an infinite<br />

number of roots for x (i.e., all x 0). Consequently, there will be a discrete point at y = 0 if the<br />

area under f x (x) is nonzero for x 0 (i.e., for the values of x that are mapped into y = 0). Using<br />

Eq. (B–68), we get<br />

where<br />

f x (y>B)<br />

y 7 0<br />

f y (y) = c B<br />

s + P(y = 0) d(y)<br />

0, y 6 0<br />

0<br />

P(y = 0) = P(x … 0) = f x (x) dx = F x (0)<br />

L -q<br />

(B–73)<br />

(B–74)<br />

Suppose that x has a Gaussian distribution with zero mean; then these equations reduce to<br />

1 >(2B 2 s 2)<br />

f y (y) = c 22pBs e-y2 , y 7 0<br />

s + 1 2 d(y)<br />

0, y 6 0<br />

(B–75)<br />

A sketch of this result is shown in Fig. B–10. For B = 1, note that the output is the same as<br />

the input for x positive (i.e., y = x 0), so that the PDF of the output is the same as the PDF of<br />

the input for y 0. For x 0, the values of x are mapped into the point y = 0, so that the PDF of<br />

1<br />

y contains a d function of weight at the point y = 0.<br />

2<br />

Proof. We will demonstrate that Eq. (B–68) is valid by partitioning the x-axis into<br />

intervals over which h(x) is monotonically increasing, monotonically decreasing, or a<br />

constant. As we have seen in Ex. B–10, when h(x) is a constant over some interval of x,<br />

a discrete point at y equal to that constant is possible. In addition, discrete points in the<br />

distribution of x will be mapped into discrete points in y, even in regions where h(x) is not<br />

a constant.<br />

Now we will demonstrate that the theorem, as described by Eq. (B–68), is correct<br />

by taking the case, for example, where y = h(x) is monotonically decreasing for x x 0<br />

and monotonically increasing for x x 0 . This is illustrated in Fig. B–11. The CDF for y<br />

is then<br />

where the + sign denotes the union operation. Then, using Eq. (B–4), we get<br />

or<br />

F y (y 0 ) = P(y … y 0 ) = P(x 1 … x … x 2 )<br />

= P[(x = x 1 ) + (x 1 6 x … x 2 )]<br />

F y (y 0 ) = P(x 1 ) + P(x 1 6 x … x 2 )<br />

(B–76)<br />

F y (y 0 ) = P(x 1 ) + F x (x 2 ) - F x (x 1 )<br />

(B–77)

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