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690 Probability and Random Variables Appendix B Proof. F(b) - F(a) = lim e:0 e 7 0 a+e b+e = lim c f(x) dx + f(x) dx L L a+e L e:0 e 7 0 b+e = lim c f(x) dxd L e:0 e 7 0 Example B–3 (Continued) c L b+e - q -q a+e a+e f(x) dx - f(x) dxd L -q a+e - q f(x) dxd Suppose that we wanted to calculate the probability of obtaining a battery having a voltage between 1.4 and 1.6 V. Using this theorem and Fig. B–5, we compute 1.6 P(1.4 6 x … 1.6) = f(x) dx = F(1.6) - F(1.4) = 0.19 L 1.4 We also realize that the probability of obtaining a 1.5-V battery is zero. Why? However, the probability of obtaining a 1.5 V ; 0.1 V battery is 0.19. Example B–4 PDF AND CDF FOR A GAUSSIAN RANDOM VARIABLE Let x be a Gaussian RV with mean m and variance s. Using MATLAB, find the values for m and s in order to give the results shown in Fig. B–5. Plot your results and compare with Fig. B–5. Using MATLAB, evaluate P(1.4 6 x … 1.6). See ExampleB_04.m for the solution. In communication systems, there are digital signals that may have discrete distributions (one discrete value for each permitted level in a multilevel signal), and there are analog signals and noise that have continuous distributions. There may also be mixed distributions, which contain discrete, as well as continuous, values. For example, these occur when a continuous signal and noise are clipped by an amplifier that is driven into saturation. THEOREM. If x is discretely distributed, then M f(x) = a P(x i ) d (x - x i ) i=1 (B–19) where M is the number of discrete events and P(x i ) is the probability of obtaining the discrete event x i . This theorem was illustrated by Example B–2, where the PDF of this discrete distribution is plotted in Fig. B–4. THEOREM. If x is discretely distributed, then † L F(a) = a P(x i ) (B–20) † M Equation (B–20) is identical to F(a) = a i = 1 P(x 1)u(a - x i ), where u(y) is a unit step function [defined in Eq. (2–49)]. i=1
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690<br />
Probability and Random Variables<br />
Appendix B<br />
Proof.<br />
F(b) - F(a) = lim<br />
e:0<br />
e 7 0<br />
a+e<br />
b+e<br />
= lim c f(x) dx + f(x) dx<br />
L L a+e L<br />
e:0<br />
e 7 0<br />
b+e<br />
= lim c f(x) dxd<br />
L<br />
e:0<br />
e 7 0<br />
Example B–3 (Continued)<br />
c<br />
L<br />
b+e<br />
- q<br />
-q<br />
a+e<br />
a+e<br />
f(x) dx - f(x) dxd<br />
L<br />
-q<br />
a+e<br />
- q<br />
f(x) dxd<br />
Suppose that we wanted to calculate the probability of obtaining a battery having a voltage<br />
between 1.4 and 1.6 V. Using this theorem and Fig. B–5, we compute<br />
1.6<br />
P(1.4 6 x … 1.6) = f(x) dx = F(1.6) - F(1.4) = 0.19<br />
L<br />
1.4<br />
We also realize that the probability of obtaining a 1.5-V battery is zero. Why? However, the probability<br />
of obtaining a 1.5 V ; 0.1 V battery is 0.19.<br />
Example B–4 PDF AND CDF FOR A GAUSSIAN RANDOM VARIABLE<br />
Let x be a Gaussian RV with mean m and variance s. Using MATLAB, find the values for m and<br />
s in order to give the results shown in Fig. B–5. Plot your results and compare with<br />
Fig. B–5. Using MATLAB, evaluate P(1.4 6 x … 1.6). See ExampleB_04.m for the solution.<br />
In communication systems, there are digital signals that may have discrete distributions<br />
(one discrete value for each permitted level in a multilevel signal), and there are analog<br />
signals and noise that have continuous distributions. There may also be mixed distributions,<br />
which contain discrete, as well as continuous, values. For example, these occur when a continuous<br />
signal and noise are clipped by an amplifier that is driven into saturation.<br />
THEOREM.<br />
If x is discretely distributed, then<br />
M<br />
f(x) = a P(x i ) d (x - x i )<br />
i=1<br />
(B–19)<br />
where M is the number of discrete events and P(x i ) is the probability of obtaining the<br />
discrete event x i .<br />
This theorem was illustrated by Example B–2, where the PDF of this discrete distribution<br />
is plotted in Fig. B–4.<br />
THEOREM. If x is discretely distributed, then †<br />
L<br />
F(a) = a P(x i )<br />
(B–20)<br />
† M<br />
Equation (B–20) is identical to F(a) = a i = 1 P(x 1)u(a - x i ), where u(y) is a unit step function<br />
[defined in Eq. (2–49)].<br />
i=1