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Sec. 2–2 Fourier Transform and Spectra 47<br />

A weaker sufficient condition for the existence of the Fourier transform is<br />

q<br />

E = |w(t)| 2 dt 6q<br />

L<br />

-q<br />

(2–32)<br />

where E is the normalized energy [Goldberg, 1961]. This is the finite-energy condition that is<br />

satisfied by all physically realizable waveforms. Thus, all physical waveforms encountered in<br />

engineering practice are Fourier transformable.<br />

It should also be noted that mathematicians sometimes use other definitions for the<br />

Fourier transform rather than Eq. (2–26). However, in these cases, the equation for the corresponding<br />

inverse transforms, equivalent to Eq. (2–30), would also be different, so that when<br />

the transform and its inverse are used together, the original w(t) would be recovered. This is a<br />

consequence of the Fourier integral theorem, which is<br />

w(t) =<br />

L<br />

q<br />

q<br />

-q L-q<br />

w(l)e j2pf(t-l) dl df<br />

(2–33)<br />

Equation (2–33) may be decomposed into Eqs. (2–26) and (2–30), as well as other definitions<br />

for Fourier transform pairs. The Fourier integral theorem is strictly true only for wellbehaved<br />

functions (i.e., physical waveforms). For example, if w(t) is an ideal square wave, then<br />

at a discontinuous point of w (l 0 ), denoted by l 0 , w(t) will have a value that is the average of<br />

the two values that are obtained for w(l)<br />

on each side of the discontinuous point .<br />

l 0<br />

Example 2–3 SPECTRUM OF AN EXPONENTIAL PULSE<br />

Let w(t) be a decaying exponential pulse that is switched on at t = 0. That is,<br />

Directly integrating the FT integral, we get<br />

or<br />

In other words, the FT pair is<br />

e e-t , t 7 0<br />

(2–34)<br />

0, t 6 0 f 4 1<br />

1 + j2pf<br />

The spectrum can also be expressed in terms of the quadrature functions by rationalizing the<br />

denominator of Eq. (2–34); thus,<br />

X(f) =<br />

See Example1_03A.m for plots.<br />

q<br />

W(f) = e -t e -j2pft dt = `<br />

L<br />

0<br />

w(t) = e e-t , t 7 0<br />

0, t 6 0<br />

W(f) =<br />

1<br />

1 + j2pf<br />

1<br />

1 + (2pf) 2 and Y(f) =<br />

-e -(1+j2pf)t q<br />

1 + j2pf `<br />

0<br />

-2pf<br />

1 + (2pf) 2

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