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46<br />

Signals and Spectra Chap. 2<br />

These evaluation techniques are developed throughout the remainder of this chapter.<br />

From Eq. (2–26), since is complex, W(f) is a complex function of frequency.<br />

W(f) may be decomposed into two real functions X(f) and Y(f) such that<br />

e -j2pft<br />

W(f) = X(f) + jY(f)<br />

(2–27)<br />

which is identical to writing a complex number in terms of pairs of real numbers that can be<br />

plotted in a two-dimensional Cartesian coordinate system. For this reason, Eq. (2–27) is<br />

sometimes called the quadrature form, or Cartesian form. Similarly, Eq. (2–26) can be<br />

written equivalently in terms of a polar coordinate system, where the pair of real functions<br />

denotes the magnitude and phase:<br />

That is,<br />

W(f) = |W(f)|e ju(f)<br />

|W(f)| = 3X 2 (f) + Y 2 (f) and u(f) = tan -1 a Y(f)<br />

X(f) b<br />

(2–28)<br />

(2–29)<br />

This is called the magnitude–phase form, or polar form. To determine whether certain<br />

frequency components are present, one would examine the magnitude spectrum ƒW(f)ƒ,<br />

which engineers sometimes loosely call the spectrum.<br />

The time waveform may be calculated from the spectrum by using the inverse Fourier<br />

transform<br />

q<br />

w(t) = W(f)e j2pft df<br />

L<br />

-q<br />

(2–30)<br />

The functions w(t) and W(f) are said to constitute a Fourier transform pair, where w(t)<br />

is the time domain description and W(f) is the frequency domain description. In this book, the<br />

time domain function is usually denoted by a lowercase letter and the frequency domain<br />

function by an uppercase letter. Shorthand notation for the pairing between the two domains<br />

will be denoted by a double arrow: w(t) 4 W(f).<br />

The waveform w(t) is Fourier transformable (i.e., sufficient conditions) if it satisfies<br />

both Dirichlet conditions:<br />

• Over any time interval of finite width, the function w(t) is single valued with a finite<br />

number of maxima and minima, and the number of discontinuities (if any) is finite.<br />

• w(t) is absolutely integrable. That is,<br />

q<br />

|w(t)| dt 6q<br />

(2–31)<br />

L-q<br />

Although these conditions are sufficient, they are not necessary. In fact, some of the examples<br />

given subsequently do not satisfy the Dirichlet conditions, and yet the Fourier transform can<br />

be found.

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