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612 Wire and Wireless Communication Applications Chap. 8 Example 8–3 RECEIVED (C/N) db FOR LINE-OF-SIGHT PROPAGATION Using Eq. (8–43), let (P EIRP ) dBw = 36, f = 4 GHz, B = 30 MHz, T syst = 154.5 K, and d = 24,787 miles. The receiving antenna is a 5-meter diameter parabola. Calculate the (CN) dB at the receiver detector input. See Example8_03.m for the solution. For digital communications systems, the BER at the digital output is a measure of performance. The BER is related to E b N 0 via the CNR. The E b N 0 -to-CNR relationship is developed in the next section. Study aid problems SA8–1 and 8–2 evaluate the BER for a DSS television receiving system. E b N 0 Link Budget for Digital Systems In digital communication systems, the probability of bit error P e for the digital signal at the detector output describes the quality of the recovered data. P e , also called the BER, is a function of the ratio of the energy per bit to the noise PSD, (E b N 0 ), as measured at the detector input. The exact relationship between P e and E b N 0 depends on the type of digital signaling used, as shown in Table 7–1 and Fig. 7–14. In this section, we evaluate the E b N 0 obtained at the detector input as a function of the communication link parameters. The energy per bit is given by E b = CT b , where C is the signal power and T b is the time required to send one bit. Using Eq. (8–40), we see that the noise PSD (one sided) is N 0 = kT syst . Thus, C N = E b>T b N 0 B where R = 1T b is the data rate (bs). Using Eq. (8–44) in Eq. (8–42), we have E b = E bR N 0 B (8–44) = P EIRPG FS G AR (8–45) N 0 kT syst R In decibel units, the E b N 0 received at the detector input in a digital communications receiver is related to the link parameters by a E b b = (P EIRP ) dBw - (L FS ) dB + a G AR b - k dB - R dB N 0 dB T syst dB (8–46) where (R) dB = 10 log (R) and R is the data rate (bs). For example, suppose that we have BPSK signaling and that an optimum detector is used in the receiver; then (E b N 0 ) dB = 8.4 dB is required for P e = 10 -4 . (See Fig. 7–14.) † Using Eq. (8–46), we see that the communication link parameters may be selected to give the required (E b N 0 ) dB of 8.4 dB. Note that as the bit rate is increased, the transmitted power has to be increased or the receiving system performance—denoted by (G AR T syst ) dB —has to be improved to maintain the required (E b N 0 ) dB of 8.4 dB. Examples of evaluating the E b N 0 link budget to obtain the BER for a DSS television receiving system are shown in SA8–1 and SA8–2. † If, in addition, coding were used with a coding gain of 3 dB (see Sec. 1–11), an E b N 0 of 5.4 dB would be required for P e = 10 -4 .
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612<br />
Wire and Wireless Communication Applications Chap. 8<br />
Example 8–3 RECEIVED (C/N) db FOR LINE-OF-SIGHT PROPAGATION<br />
Using Eq. (8–43), let (P EIRP ) dBw = 36, f = 4 GHz, B = 30 MHz, T syst = 154.5 K, and d = 24,787<br />
miles. The receiving antenna is a 5-meter diameter parabola. Calculate the (CN) dB at the receiver<br />
detector input. See Example8_03.m for the solution.<br />
For digital communications systems, the BER at the digital output is a measure of<br />
performance. The BER is related to E b N 0 via the CNR. The E b N 0 -to-CNR relationship is<br />
developed in the next section. Study aid problems SA8–1 and 8–2 evaluate the BER for a DSS<br />
television receiving system.<br />
E b N 0 Link Budget for Digital Systems<br />
In digital communication systems, the probability of bit error P e for the digital signal at the<br />
detector output describes the quality of the recovered data. P e , also called the BER, is a function<br />
of the ratio of the energy per bit to the noise PSD, (E b N 0 ), as measured at the detector<br />
input. The exact relationship between P e and E b N 0 depends on the type of digital signaling<br />
used, as shown in Table 7–1 and Fig. 7–14. In this section, we evaluate the E b N 0 obtained at<br />
the detector input as a function of the communication link parameters.<br />
The energy per bit is given by E b = CT b , where C is the signal power and T b is the<br />
time required to send one bit. Using Eq. (8–40), we see that the noise PSD (one sided) is<br />
N 0 = kT syst . Thus,<br />
C<br />
N = E b>T b<br />
N 0 B<br />
where R = 1T b is the data rate (bs). Using Eq. (8–44) in Eq. (8–42), we have<br />
E b<br />
= E bR<br />
N 0 B<br />
(8–44)<br />
= P EIRPG FS G AR<br />
(8–45)<br />
N 0 kT syst R<br />
In decibel units, the E b N 0 received at the detector input in a digital communications receiver<br />
is related to the link parameters by<br />
a E b<br />
b = (P EIRP ) dBw - (L FS ) dB + a G AR<br />
b - k dB - R dB<br />
N 0 dB<br />
T syst dB<br />
(8–46)<br />
where (R) dB = 10 log (R) and R is the data rate (bs).<br />
For example, suppose that we have BPSK signaling and that an optimum detector is used<br />
in the receiver; then (E b N 0 ) dB = 8.4 dB is required for P e = 10 -4 . (See Fig. 7–14.) † Using<br />
Eq. (8–46), we see that the communication link parameters may be selected to give the required<br />
(E b N 0 ) dB of 8.4 dB. Note that as the bit rate is increased, the transmitted power has to be<br />
increased or the receiving system performance—denoted by (G AR T syst ) dB —has to be improved<br />
to maintain the required (E b N 0 ) dB of 8.4 dB. Examples of evaluating the E b N 0 link budget to<br />
obtain the BER for a DSS television receiving system are shown in SA8–1 and SA8–2.<br />
† If, in addition, coding were used with a coding gain of 3 dB (see Sec. 1–11), an E b N 0 of 5.4 dB would be<br />
required for P e = 10 -4 .