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Sec. 7–2 Performance of Baseband Binary Systems 503 ( s 1 (t) r(t)= or +n(t) s 2 (t) ( N 0 Low-pass filter or matched filter r 0 (t) Sample and hold r 0 (t 0 )=r 0 Threshold device –V T ~ m V T r 0 Digital output m ~ where p n (f)= 2 Figure 7–6 Receiver for bipolar signaling. (a) Receiver f(r 0 |-A sent) f f(r 0 | s 2 A sent) f(r 0 |+A sent) Q (V T /Í 0 ) Q (V T /Í 0 ) –A –V T V T ±A r 0 P (error| – A sent)=Q[(A – V T )/Í 0 ] P (error| ± A sent)=Q[(A – V T )/Í 0 ] (b) Conditional PDFs or P e L Qa V T b + 1 s 0 2 Qa A - V T b s 0 using calculus, we find that the optimum value of V T that gives the minimum BER is V T = A For systems with reasonably low (i.e., usable) BERs, A 7 s 0 , so that the 2 + s 0 2 A ln2. optimum threshold becomes approximately V T = A/2, the BER is P e = 3 2 Qa A 2s 0 b For the case of a receiver with a low-pass filter that has a bipolar signal plus white noise at its input, s 2 0 = N 0 B. Thus, the BER is A 2 P e = 3 2 Q¢ C4N 0 B ≤ (low-pass filter) (7–28a) where the PSD of the input noise is N 0 /2 and the equivalent bandwidth of the filter is B Hz. If a matched filter is used, its output SNR is, using Eq. (6–161), a S N b out = A2 s 0 2 = 2E d N 0

Sec. 7–2 Performance of Baseband Binary Systems 503<br />

(<br />

s 1 (t)<br />

r(t)= or +n(t)<br />

s 2 (t)<br />

(<br />

N 0<br />

Low-pass filter<br />

or<br />

matched filter<br />

r 0 (t)<br />

Sample<br />

and hold<br />

r 0 (t 0 )=r 0<br />

Threshold device<br />

–V T<br />

~ m<br />

V T r 0<br />

Digital<br />

output m ~<br />

where p n (f)= 2<br />

Figure 7–6 Receiver for bipolar signaling.<br />

(a) Receiver<br />

f(r 0 |-A sent)<br />

f<br />

f(r 0 | s 2 A sent)<br />

f(r 0 |+A sent)<br />

Q (V T /Í 0 ) Q (V T /Í 0 )<br />

–A –V T V T<br />

±A<br />

r 0<br />

P (error| – A sent)=Q[(A – V T )/Í 0 ] P (error| ± A sent)=Q[(A – V T )/Í 0 ]<br />

(b) Conditional PDFs<br />

or<br />

P e L Qa V T<br />

b + 1 s 0 2 Qa A - V T<br />

b<br />

s 0<br />

using calculus, we find that the optimum value of V T that gives the minimum BER is<br />

V T = A For systems with reasonably low (i.e., usable) BERs, A 7 s 0 , so that the<br />

2 + s 0 2<br />

A ln2.<br />

optimum threshold becomes approximately V T = A/2, the BER is<br />

P e = 3 2 Qa A<br />

2s 0<br />

b<br />

For the case of a receiver with a low-pass filter that has a bipolar signal plus white noise at its<br />

input, s 2 0 = N 0 B. Thus, the BER is<br />

A 2<br />

P e = 3 2 Q¢ C4N 0 B ≤<br />

(low-pass filter)<br />

(7–28a)<br />

where the PSD of the input noise is N 0 /2 and the equivalent bandwidth of the filter is B Hz.<br />

If a matched filter is used, its output SNR is, using Eq. (6–161),<br />

a S N b out<br />

= A2<br />

s 0<br />

2 = 2E d<br />

N 0

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