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Sec. 7–2 Performance of Baseband Binary Systems 503 ( s 1 (t) r(t)= or +n(t) s 2 (t) ( N 0 Low-pass filter or matched filter r 0 (t) Sample and hold r 0 (t 0 )=r 0 Threshold device –V T ~ m V T r 0 Digital output m ~ where p n (f)= 2 Figure 7–6 Receiver for bipolar signaling. (a) Receiver f(r 0 |-A sent) f f(r 0 | s 2 A sent) f(r 0 |+A sent) Q (V T /Í 0 ) Q (V T /Í 0 ) –A –V T V T ±A r 0 P (error| – A sent)=Q[(A – V T )/Í 0 ] P (error| ± A sent)=Q[(A – V T )/Í 0 ] (b) Conditional PDFs or P e L Qa V T b + 1 s 0 2 Qa A - V T b s 0 using calculus, we find that the optimum value of V T that gives the minimum BER is V T = A For systems with reasonably low (i.e., usable) BERs, A 7 s 0 , so that the 2 + s 0 2 A ln2. optimum threshold becomes approximately V T = A/2, the BER is P e = 3 2 Qa A 2s 0 b For the case of a receiver with a low-pass filter that has a bipolar signal plus white noise at its input, s 2 0 = N 0 B. Thus, the BER is A 2 P e = 3 2 Q¢ C4N 0 B ≤ (low-pass filter) (7–28a) where the PSD of the input noise is N 0 /2 and the equivalent bandwidth of the filter is B Hz. If a matched filter is used, its output SNR is, using Eq. (6–161), a S N b out = A2 s 0 2 = 2E d N 0
- Page 1002: ` ` ` Sec. 6-10 Appendix: Proof of
- Page 1006: ` Sec. 6-11 Study-Aid Examples 479
- Page 1010: Problems 481 SA6-4 PSD for a Bandpa
- Page 1014: Problems 483 The power of n 1 (t) i
- Page 1018: Problems 485 1 2 x (f) = e N 0, ƒ
- Page 1022: Problems 487 6-42 A bandpass WSS ra
- Page 1026: Problems 489 6-54 A narrowband-sign
- Page 1030: Problems 491 6-60 Let be a wideband
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- Page 1060: 506 Performance of Communication Sy
- Page 1064: 508 Upper channel Receiver r(t)=s(t
- Page 1068: 510 Performance of Communication Sy
- Page 1072: 512 Performance of Communication Sy
- Page 1076: 514 Performance of Communication Sy
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- Page 1084: 518 DPSK signal plus noise in Bandp
- Page 1088: 520 QPSK signal plus noise (data ra
- Page 1092: TABLE 7-1 COMPARISON OF DIGITALSIGN
- Page 1096: 524 Performance of Communication Sy
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Sec. 7–2 Performance of Baseband Binary Systems 503<br />
(<br />
s 1 (t)<br />
r(t)= or +n(t)<br />
s 2 (t)<br />
(<br />
N 0<br />
Low-pass filter<br />
or<br />
matched filter<br />
r 0 (t)<br />
Sample<br />
and hold<br />
r 0 (t 0 )=r 0<br />
Threshold device<br />
–V T<br />
~ m<br />
V T r 0<br />
Digital<br />
output m ~<br />
where p n (f)= 2<br />
Figure 7–6 Receiver for bipolar signaling.<br />
(a) Receiver<br />
f(r 0 |-A sent)<br />
f<br />
f(r 0 | s 2 A sent)<br />
f(r 0 |+A sent)<br />
Q (V T /Í 0 ) Q (V T /Í 0 )<br />
–A –V T V T<br />
±A<br />
r 0<br />
P (error| – A sent)=Q[(A – V T )/Í 0 ] P (error| ± A sent)=Q[(A – V T )/Í 0 ]<br />
(b) Conditional PDFs<br />
or<br />
P e L Qa V T<br />
b + 1 s 0 2 Qa A - V T<br />
b<br />
s 0<br />
using calculus, we find that the optimum value of V T that gives the minimum BER is<br />
V T = A For systems with reasonably low (i.e., usable) BERs, A 7 s 0 , so that the<br />
2 + s 0 2<br />
A ln2.<br />
optimum threshold becomes approximately V T = A/2, the BER is<br />
P e = 3 2 Qa A<br />
2s 0<br />
b<br />
For the case of a receiver with a low-pass filter that has a bipolar signal plus white noise at its<br />
input, s 2 0 = N 0 B. Thus, the BER is<br />
A 2<br />
P e = 3 2 Q¢ C4N 0 B ≤<br />
(low-pass filter)<br />
(7–28a)<br />
where the PSD of the input noise is N 0 /2 and the equivalent bandwidth of the filter is B Hz.<br />
If a matched filter is used, its output SNR is, using Eq. (6–161),<br />
a S N b out<br />
= A2<br />
s 0<br />
2 = 2E d<br />
N 0