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500<br />

Performance of Communication Systems Corrupted by Noise Chap. 7<br />

r(t)=s(t)+n(t)<br />

(<br />

s 1 (t)<br />

r(t)= or<br />

s 2 (t)<br />

(<br />

+n(t)<br />

N 0<br />

Low-pass filter<br />

or<br />

matched filter<br />

H( f )<br />

r 0 (t) Sample<br />

and<br />

r 0 (t 0 )<br />

hold<br />

where p n (f)= 2<br />

Figure 7–4 Receiver for baseband binary signaling.<br />

Threshold<br />

device<br />

~ m<br />

0<br />

V T<br />

r 0<br />

Threshold<br />

device<br />

m ~<br />

(a) Receiver<br />

s(t)<br />

t<br />

r(t)<br />

(b) Unipolar Signaling<br />

t<br />

s(t)<br />

t<br />

r(t)<br />

t<br />

(c) Polar Signaling<br />

the filter. † Thus, s 01 (t 0 ) ≈ A and s 02 (t 0 ) ≈ 0. The noise power at the output of the filter is<br />

s 2 0 = (N 0 >2) (2B), where B is the equivalent bandwidth of the filter. The optimum threshold<br />

setting is then V T = 1 2 A. When we use Eq. (7–17), the BER is<br />

A<br />

P e = Q¢ 2<br />

≤ (low-pass filter)<br />

C 4N 0 B<br />

for a receiver that uses an LPF with an equivalent bandwidth of B.<br />

(7–24a)<br />

† From Eq. (3–39b), the PSD of a unipolar signal (rectangular pulse shape) is proportional to<br />

[sin (pfT)/(pfT)] 2 , so that the second null bandwidth is 2/T. Referring to study-aid examples SA7–1 and SA7–2, it<br />

is shown that if the equivalent bandwidth of the LPF is greater than 2/T, the filtered signal will consist of pulses that<br />

are almost rectangular in shape and the peak values of the pulses are approximately equal to A.

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