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Problems 489<br />

6–54 A narrowband-signal-plus-Gaussian noise process is represented by the equation<br />

r(t) = A cos(v c t + u c ) + x(t) cos(v c t + u c ) - y(t) sin(v c t + u c )<br />

where A cos (v c t + u c ) is a sinusoidal carrier and the remaining terms are the bandpass noise with<br />

independent Gaussian I and Q components. Let the noise have an RMS value of s and a mean<br />

of 0. The signal-plus-noise process appears at the input to an envelope detector. Show that the<br />

PDF for the output of the envelope detector is<br />

R +A 2 )/(2s 2 )] RA<br />

f(R) = c s 2 e-[(R2 I 0 P<br />

s 2 Q , R Ú 0<br />

0, R 6 0<br />

where<br />

I 0 (z) ! 1<br />

2p L0<br />

2p<br />

e z cos u du<br />

is the modified Bessel function of the first kind of zero order. f(R) is known as a Rician PDF in<br />

honor of the late S. O. Rice, who was an outstanding engineer at Bell Telephone Laboratories.<br />

6–55 Assume that<br />

is a known signal. This signal plus white noise is present at the input to a matched filter.<br />

(a) Design a matched filter for s(t). Sketch waveforms analogous to those shown in Fig. 6–16.<br />

(b) Sketch the waveforms for the correlation processor shown in Fig. 6–18.<br />

★ 6–56 A baseband digital communication system uses polar signaling with a bit rate of R = 2,000 bits/s.<br />

The transmitted pulses are rectangular and the frequency response of channel filter is<br />

where B = 6,000 Hz. The filtered pulses are the input to a receiver that uses integrate-and-dump<br />

processing, as illustrated in Fig. 6–17. Examine the integrator output for ISI. In particular,<br />

(a) Plot the integrator output when a binary “1” is sent.<br />

(b) Plot the integrator output for an all-pass channel, and compare this result with that obtained<br />

in part (a).<br />

6–57 Refer to Fig. 6–19 for the detection of a BPSK signal. Suppose that the BPSK signal at the<br />

input is<br />

where<br />

A<br />

s(t) = c T t cos v ct, 0 … t … T<br />

0, t otherwise<br />

H c (f) =<br />

r(t) = s(t) = a<br />

7<br />

p(t) = e e-t cos v c t, 0 6 t 6 T<br />

0, t otherwise<br />

and the binary data d n is the 8-bit string {+1, -1, -1, +1, +1, -1, +1, -1}. Use MATLAB to<br />

n = 0<br />

B<br />

B + jf<br />

d n p(t - nT)

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