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Kinematics and dynamics of rigid bodies 69<br />

Z 3<br />

Z 2<br />

<br />

Body 2<br />

X 3<br />

<br />

X 2<br />

Y 2 ,Y 3<br />

O 2 ,O 3<br />

Fig. 2.35<br />

Vehicle body co-ordinate system<br />

tank. The frame O 2 shown in Figure 2.35 is also positioned at the mass<br />

centre and has its Y 2 -axis coincident with the Y 3 -axis of frame O 3 . The<br />

frame O 2 represents the principal axes of the vehicle body and is obtained<br />

by a transformation from O 3 represented by the rotation through an angle <br />

about the Y 2 - and Y 3 -axes.<br />

In determining the products of inertia for this body it can be seen that for<br />

every element of mass with a positive y co-ordinate there exists an equivalent<br />

element with a negative y co-ordinate. As a result we get<br />

I I xy d m 0<br />

xy<br />

yx<br />

I I yz d m 0<br />

yz<br />

zy<br />

∫<br />

∫<br />

The inertia matrix for Body 2 [I 2 ] 2/3 measured from frame O 2 and referred<br />

to O 3 is therefore<br />

⎡Ixx<br />

0 Ixz<br />

⎤<br />

[ I2] 2 / 3<br />

⎢<br />

0 I2<br />

0<br />

⎥<br />

⎢<br />

⎥<br />

(2.215)<br />

⎣⎢<br />

Ixz<br />

0 Izz<br />

⎦⎥<br />

From this it can be seen that the y-axis is a principal axis and is normal to<br />

the plane of symmetry. The principal moment of inertia I 2 is therefore<br />

equal to I yy . From section 2.2.7 we can see that the matrix [T 3 ] 2 that transforms<br />

from frame O 3 to O 2 is given by<br />

⎡cos 0 sin<br />

⎤<br />

[ T 3 ] 2 <br />

⎢<br />

0 1 0<br />

⎥<br />

⎢<br />

⎥<br />

⎣⎢<br />

sin 0 cos⎦⎥<br />

(2.216)<br />

From (2.206) we can see that using the transformation matrix [T 3 ] 2 given<br />

for this particular case will lead to<br />

[I 2 ] 2/2 [T 3 ] 2 [I 2 ] 2/3 [T 3 ] T 2

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