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Kinematics and dynamics of rigid bodies 47 { A } d { } R R d t { } d 2 1 d t { 2 } { } PQ 1 1 PQ 1 PQ 1 Since it is known that d d { RPQ t } { VPQ } 1 1 (2.103) (2.104) d dt { } { } 2 1 2 1 (2.105) We can therefore write {A PQ } 1 { 2 } 1 {V PQ } 1 { 2 } 1 {R PQ } 1 (2.106) Since it is also known that {V PQ } 1 { 2 } 1 {R PQ } 1 (2.107) This leads to the expression {A PQ } 1 { 2 } 1 {{ 2 } 1 {R PQ } 1 } { 2 } 1 {R PQ } 1 (2.108) The acceleration vector {A PQ } 1 can be considered to have a centripetal component {APQ} p 1 and a transverse component {APQ} t 1 . This is illustrated in Figure 2.20 where one of the arms from a double wishbone suspension system is shown. In this case the centripetal component of acceleration is given by {APQ} p 1 { 2 } 1 {{ 2 } 1 {R PQ } 1 } (2.109) Note that as the suspension arm is constrained to rotate about the axis NQ, ignoring at this stage any possible deflection due to compliance in the suspension bushes, the vectors { 2 } 1 for the angular velocity of Body 2 and { 2 } 1 for the angular acceleration would act along the axis of rotation through NQ. The components of these vectors would adopt signs consistent with producing a positive rotation about this axis as shown in Figure 2.20. When setting up the equations to solve a velocity or acceleration analysis it may be desirable to reduce the number of unknowns based on the knowledge that a particular body is constrained to rotate about a known axis as Z 1 {A PQ } 1 O 1 X Y 1 1 p N {APQ } 1 Q {ω 2 } 1 {α 2 } 1 Body 2 t {A PQ } 1 {V PQ } 1 P Fig. 2.20 Centripetal and transverse components of acceleration vectors

48 Multibody Systems Approach to Vehicle Dynamics shown here. The velocity vector { 2 } 1 could, for example, be represented as follows: { 2 } 1 f 2 {R QN } 1 (2.110) In this case, since { 2 } 1 is parallel to the relative position vector {R QN } 1 a scale factor f 2 can be introduced. This would reduce the problem from the three unknown components, x 2, y 2 and z 2 of the vector { 2 } 1 to a single unknown f 2 . A similar approach could be used for an acceleration analysis with, for example, { 2 } 1 f 2 {R QN } 1 (2.111) It can also be seen from Figure 2.20 that the centripetal acceleration acts towards, and is perpendicular to the axis of rotation of the body. This relationship can be proved having found the centripetal acceleration by use of the dot product with {APQ} p 1 • {R QN } 1 0 (2.112) The transverse component of acceleration is given by {APQ} t 1 { 2 } 1 {R PQ } 1 (2.113) Note that the transverse component of acceleration is also perpendicular to, in this case, the vector {R PQ } 1 as defined by the dot product with {APQ} t 1 • {R PQ } 1 0 (2.114) Note that although the vector {A t PQ} 1 is shown to be acting in the same direction as the vector {V PQ } 1 in Figure 2.20, this may not necessarily be the case. A reversal of {A t PQ} 1 would correspond to a reversal of { 2 } 1 . This would indicate that point P is moving in a certain direction but in fact decelerating. The resultant acceleration vector {A PQ } 1 is found to give the expression shown in equation (2.115) using the triangle law to add the centripetal and transverse components as follows: {A PQ } 1 {APQ} p 1 {A t PQ} 1 (2.115) For the example shown here in Figure 2.20 the analysis may often focus on suspension movement only and assume the vehicle body to be fixed and not moving. This would mean that the velocity or acceleration at point Q, {A Q } 1 would be zero. Since we can say, based on the triangle law, that {A PQ } 1 {A P } 1 {A Q } 1 (2.116) it therefore follows in this case that since Q is fixed: {A P } 1 {A PQ } 1 (2.117) Note that the same principle could be used when solving the velocities for this problem and that we could write {V P } 1 {V PQ } 1 (2.118) Finally it should be noted for the particular example, shown here in Figure 2.20, that we could work from either point Q or point N when solving for the velocities or accelerations and obtain the same answers for the velocity or acceleration at point P. Combining the relative acceleration already obtained for points on a rigid body translating and rotating in space with sliding motion will introduce

Kinematics and dynamics of rigid bodies 47<br />

{ A }<br />

d<br />

{ } R<br />

R<br />

d t<br />

{ } d<br />

2 <br />

1 <br />

d t<br />

{ 2<br />

} { }<br />

PQ 1 1 PQ 1 PQ 1<br />

Since it is known that<br />

d<br />

d { RPQ<br />

t<br />

} { VPQ<br />

}<br />

1 1<br />

(2.103)<br />

(2.104)<br />

d<br />

dt { }<br />

{ }<br />

2 1 2 1<br />

(2.105)<br />

We can therefore write<br />

{A PQ } 1 { 2 } 1 {V PQ } 1 { 2 } 1 {R PQ } 1 (2.106)<br />

Since it is also known that<br />

{V PQ } 1 { 2 } 1 {R PQ } 1 (2.107)<br />

This leads to the expression<br />

{A PQ } 1 { 2 } 1 {{ 2 } 1 {R PQ } 1 } { 2 } 1 {R PQ } 1 (2.108)<br />

The acceleration vector {A PQ } 1 can be considered to have a centripetal<br />

component {APQ} p 1 and a transverse component {APQ} t 1 . This is illustrated<br />

in Figure 2.20 where one of the arms from a double wishbone suspension<br />

system is shown.<br />

In this case the centripetal component of acceleration is given by<br />

{APQ} p 1 { 2 } 1 {{ 2 } 1 {R PQ } 1 } (2.109)<br />

Note that as the suspension arm is constrained to rotate about the axis NQ,<br />

ignoring at this stage any possible deflection due to compliance in the suspension<br />

bushes, the vectors { 2 } 1 for the angular velocity of Body 2 and<br />

{ 2 } 1 for the angular acceleration would act along the axis of rotation through<br />

NQ. The components of these vectors would adopt signs consistent with<br />

producing a positive rotation about this axis as shown in Figure 2.20.<br />

When setting up the equations to solve a velocity or acceleration analysis it<br />

may be desirable to reduce the number of unknowns based on the knowledge<br />

that a particular body is constrained to rotate about a known axis as<br />

Z 1<br />

{A PQ } 1<br />

O 1<br />

X<br />

Y 1 1<br />

p N<br />

{APQ } 1<br />

Q<br />

{ω 2 } 1<br />

{α 2 } 1 Body 2<br />

t<br />

{A PQ } 1<br />

{V PQ } 1<br />

P<br />

Fig. 2.20<br />

Centripetal and transverse components of acceleration vectors

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