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46 Multibody Systems Approach to Vehicle Dynamics<br />

points P and Q are fixed in the same rigid body, Body 2. As such there can<br />

be no component of motion along the line PQ and any relative motion must<br />

therefore be perpendicular to this line.<br />

This relationship can be expressed mathematically in two ways. The first of<br />

these uses the vector dot product to enforce perpendicularity as shown in<br />

equation (2.98):<br />

{V PQ } 1 • {R PQ } 1 0 (2.98)<br />

The second method uses the vector cross product as shown in equation<br />

(2.99):<br />

{V PQ } 1 { 2 } 1 {R PQ } 1 (2.99)<br />

More often than not we use the cross product as this will yield the angular<br />

velocity vector { 2 } 1 . This may be required for a later acceleration analysis.<br />

In developing the equations to solve the velocities in a system of interconnected<br />

rigid bodies the triangle law of vector addition can also be used<br />

as shown in equation (2.100):<br />

{V P } 1 {V Q } 1 {V PQ } 1 (2.100)<br />

2.5 Acceleration analysis<br />

Given that acceleration is the time rate of change of velocity we can<br />

develop the equations required for an acceleration analysis using the vectors<br />

shown in Figure 2.19.<br />

It is possible to develop equations that would yield the relative acceleration<br />

vector {A PQ } 1 using the angular velocity vector { 2 } 1 and the angular<br />

acceleration vector { 2 } 1 as follows:<br />

d<br />

{ APQ} { VPQ}<br />

dt<br />

1 1<br />

(2.101)<br />

{ A }<br />

d<br />

RPQ<br />

d t<br />

{{ 2<br />

} { } }<br />

PQ 1 1 1<br />

(2.102)<br />

{V PQ } 1<br />

{ω 2 } 1<br />

{A PQ } 1<br />

{α 2 } 1<br />

P<br />

O1<br />

X 1<br />

Z 1<br />

Y 1<br />

Q<br />

{R PQ } 1<br />

Body 2<br />

Fig. 2.19<br />

Relative acceleration vector

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