01.05.2017 Views

4569846498

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Kinematics and dynamics of rigid bodies 27<br />

{A} 1<br />

{B} 1<br />

Fig. 2.6<br />

Application of the dot product to enforce perpendicularity<br />

{C} 1<br />

{B} 1<br />

{A} 1<br />

θ<br />

Fig. 2.7<br />

Vector cross product<br />

The magnitude of {C} 1 is defined as<br />

|C| |A| |B| sin (2.14)<br />

The direction of {C} 1 is defined by a positive rotation about {C} 1 rotating<br />

{A} 1 into line with {B} 1 . The calculation of {A} 1 {B} 1 requires {A} 1 to<br />

be arranged in skew-symmetric form as follows:<br />

⎡ 0<br />

{} C 1 { A} 1 { B} 1 [ A]<br />

1{}<br />

B 1 <br />

⎢<br />

Az<br />

⎢<br />

⎣⎢<br />

Ay<br />

Multiplying this out would give the vector {C} 1 :<br />

⎡AzBy<br />

AyBz⎤<br />

{} C 1 ⎢<br />

AzBx AxBz<br />

⎥<br />

⎢<br />

⎥<br />

⎣⎢<br />

AyBx<br />

AxBy⎦⎥<br />

Az<br />

Ay ⎤<br />

Ax<br />

⎥<br />

⎥<br />

0 ⎦⎥<br />

(2.15)<br />

(2.16)<br />

Exchange of {A} 1 and {B} 1 will show that the cross product operation is not<br />

commutative and that<br />

{A} 1 {B} 1 {B} 1 {A} 1 (2.17)<br />

0<br />

Ax<br />

⎡Bx⎤<br />

⎢<br />

By<br />

⎥<br />

⎢ ⎥<br />

⎣⎢<br />

Bz⎦⎥

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!