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26 Multibody Systems Approach to Vehicle Dynamics<br />

{B} 1<br />

θ<br />

{A} 1<br />

Fig. 2.5<br />

Vector dot product<br />

2.2.2 The dot (scalar) product<br />

The dot, or scalar, product {A} 1 • {B} 1 of the vectors {A} 1 and {B} 1 yields a<br />

scalar C with magnitude equal to the product of the magnitude of each vector<br />

and the cosine of the angle between them.<br />

Thus:<br />

{A} 1 • {B} 1 |C| |A| |B| cos (2.8)<br />

The calculation of {A} 1 • {B} 1 requires the solution of<br />

{A} 1 • {B} 1 {A} T 1 {B} 1 AxBx AyBy AzBz (2.9)<br />

⎡Bx⎤<br />

T<br />

where {} B 1 <br />

⎢<br />

By<br />

⎥<br />

and {} A 1 [ Ax Ay Az]<br />

⎢ ⎥<br />

⎣⎢<br />

Bz⎦⎥<br />

(2.10)<br />

The T superscript in {A} 1 T indicates that the vector is transposed.<br />

Clearly {A} 1 • {B} 1 {B} 1 • {A} 1 and the dot product is a commutative<br />

operation. The physical significance of the dot product will become apparent<br />

later but at this stage it can be seen that the angle between two vectors<br />

{A} 1 and {B} 1 can be obtained from<br />

cos { A}<br />

1<br />

{} B 1<br />

•<br />

| A|| B|<br />

(2.11)<br />

A particular case which is useful in the formulation of constraints representing<br />

joints and the like is the situation when {A} 1 and {B} 1 are perpendicular<br />

making cos 0.<br />

As can be seen in Figure 2.6 the equation that enforces the perpendicularity<br />

of the two spindles in the universal joint can be obtained from<br />

{A} 1 • {B} 1 0 (2.12)<br />

2.2.3 The cross (vector) product<br />

The cross, or vector, product of two vectors, {A} 1 and {B} 1 , is another vector<br />

{C} 1 given by<br />

{C} 1 {A} 1 {B} 1 (2.13)<br />

The vector {C} 1 is perpendicular to the plane containing {A} 1 and {B} 1 as<br />

shown in Figure 2.7.

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