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232 Multibody Systems Approach to Vehicle Dynamics<br />

Multiplying out the matrices in (4.289) yields the next set of three equations:<br />

Equation 10 15F A31y 239F A31z 1F B31y 239F B31z 42 521f S2 0<br />

(4.290)<br />

Equation 11 15F A31x 115F A31z 1F B31x 115F B31z 69f S2 0<br />

(4.291)<br />

Equation 12 239F A31x 115F A31y 239F B31x 115F B31y 294f S2 0<br />

(4.292)<br />

Consider last Body 4 and the equations required for force equilibrium:<br />

∑{F 4 } 1 {0} 1 (4.293)<br />

{F P41 } 1 {F D34 } 1 {F G24 } 1 f S1 {R JH } 1 {0} 1 (4.294)<br />

⎡ 0 ⎤ ⎡FD34x⎤<br />

⎡FG24x⎤<br />

⎡ 0 ⎤ ⎡0⎤<br />

⎢<br />

0<br />

⎥ ⎢ ⎥ ⎢ ⎥<br />

34<br />

24 1 228 0 N<br />

⎢ ⎥ ⎢<br />

F<br />

⎢ ⎥ ⎢ ⎥<br />

D y⎥<br />

<br />

⎢<br />

FG<br />

y⎥<br />

fS<br />

<br />

⎢ ⎥ ⎢ ⎥<br />

⎣⎢<br />

10 000⎦⎥<br />

⎣⎢<br />

FD34z⎦⎥<br />

⎣⎢<br />

FG24z⎦⎥<br />

⎣⎢<br />

8 ⎦⎥<br />

⎣⎢<br />

0⎦⎥<br />

(4.295)<br />

The summation of forces in (4.295) leads to the next set of three equations:<br />

Equation 13 F D34x F G24x 0 (4.296)<br />

Equation 14 F D34y F G24y 228f S1 0 (4.297)<br />

Equation 15 F D34z F G24z 8f S1 10 000 (4.298)<br />

Taking moments about point G for the forces acting on Body 4 gives<br />

∑{M G4 } 1 {0} 1 (4.299)<br />

{R PG } 1 {F P41 } 1 {R DG } 1 {F D34 } 1 {R HG } 1 f S1 {R JH } 1 {0} 1<br />

(4.300)<br />

⎡ 0 176 58⎤<br />

⎡ 0 ⎤ ⎡ 0 216<br />

31⎤<br />

⎡F<br />

⎢<br />

176 0 7<br />

⎥ ⎢<br />

0<br />

⎥<br />

<br />

⎢<br />

216 0 19<br />

⎥ ⎢<br />

⎢<br />

⎥ ⎢ ⎥ ⎢<br />

⎥ ⎢<br />

F<br />

⎣⎢<br />

58 7 0 ⎦⎥<br />

⎣⎢<br />

10 000⎦⎥<br />

⎣⎢<br />

31 19<br />

0 ⎦⎥<br />

⎣⎢<br />

F<br />

D34x<br />

D34y<br />

D34z<br />

⎡ 0 267 75⎤<br />

⎡ 0 ⎤ ⎡0⎤<br />

f<br />

⎢<br />

1 267 0 163<br />

⎥ ⎢<br />

S 228<br />

⎥<br />

<br />

⎢<br />

0<br />

⎥<br />

Nmm<br />

⎢<br />

⎥ ⎢ ⎥ ⎢ ⎥<br />

⎣⎢<br />

75 163 0 ⎦⎥<br />

⎣⎢<br />

8 ⎦⎥<br />

⎣⎢<br />

0⎦⎥<br />

(4.301)<br />

Multiplying out the matrices in (4.301) yields the next set of three equations:<br />

Equation 16 216F D34y 31F D34z 60 276f S1 580 000 (4.302)<br />

Equation 17 216F D34x 19F D34z 1304f S1 0 70 000 (4.303)<br />

Equation 18 31F D34x 19F D34y 37 164f S1 0 (4.304)<br />

Finally applying the vector dot product to ensure that no thrust for the force<br />

{F F21 } 1 acts along the axis E–F gives<br />

{F F21 } 1 • {R EF } 1 0 (4.305)<br />

⎤<br />

⎥<br />

⎥<br />

⎦⎥

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