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Modelling and analysis of suspension systems 231<br />

Equation 2 F E21y F F21y F G24y 0 (4.273)<br />

Equation 3 F E21z F F21z F G24z 0 (4.274)<br />

Taking moments about point G for the forces acting on Body 2 gives<br />

∑{M G2 } 1 {0} 1 (4.275)<br />

{R EG } 1 {F E21 } 1 {R FG } 1 {F F21 } 1 {0} 1 (4.276)<br />

⎡ 0 9 275⎤<br />

⎡F<br />

⎢<br />

9 0 115<br />

⎥ ⎢<br />

⎢<br />

⎥ ⎢<br />

F<br />

⎣⎢<br />

275 115 0 ⎦⎥<br />

⎣⎢<br />

F<br />

⎤ ⎡0⎤<br />

⎥<br />

<br />

⎢<br />

0<br />

⎥<br />

⎥<br />

N mm<br />

⎢ ⎥<br />

⎦⎥<br />

⎣⎢<br />

0⎦⎥<br />

(4.277)<br />

Multiplying out the matrices in (4.277) yields the next set of three equations:<br />

Equation 4 9F E21y 275F E21z 9F F21y 275F F21z 0 (4.278)<br />

Equation 5 9F E21x 115F E21z 9F F21x 115F F21z 0 (4.279)<br />

Equation 6 275F E21x 115F E21y 275F F21x 115F F21y 0 (4.280)<br />

Consider next Body 3 and the equations required for force equilibrium:<br />

∑{F 3 } 1 {0} 1 (4.281)<br />

{F A31 } 1 {F B31 } 1 f S2 {R CI } 1 {F D34 } 1 {0} 1 (4.282)<br />

⎡F<br />

⎢<br />

⎢<br />

F<br />

⎣⎢<br />

F<br />

A31x<br />

A31y<br />

A31z<br />

E21x<br />

E21y<br />

E21z<br />

⎤ ⎡FB31x⎤<br />

⎡ 3 ⎤ ⎡F<br />

⎥<br />

⎥<br />

<br />

⎢<br />

F<br />

⎥<br />

⎢ B31y⎥<br />

f<br />

⎢<br />

S2<br />

9<br />

⎥<br />

<br />

⎢<br />

F<br />

⎢ ⎥ ⎢<br />

⎦⎥<br />

⎣⎢<br />

FB31z⎦⎥<br />

⎣⎢<br />

436⎦⎥<br />

⎣⎢<br />

F<br />

⎤ ⎡ 0 9 275⎤<br />

⎡F<br />

⎥<br />

<br />

⎢<br />

⎥<br />

9 0 115<br />

⎥ ⎢<br />

⎢<br />

⎥ ⎢<br />

F<br />

⎦⎥<br />

⎣⎢<br />

275 115 0 ⎦⎥<br />

⎣⎢<br />

F<br />

D34x<br />

D34y<br />

D34z<br />

⎤ ⎡0⎤<br />

⎥<br />

⎥<br />

<br />

⎢<br />

0<br />

⎥<br />

N<br />

⎢ ⎥<br />

⎦⎥<br />

⎣⎢<br />

0⎦⎥<br />

F21x<br />

F21y<br />

F21z<br />

(4.283)<br />

The summation of forces in (4.283) leads to the next set of three equations:<br />

Equation 7 F A31x F B31x 3f S2 F D34x 0 (4.284)<br />

Equation 8 F A31y F B31y 9f S2 F D34y 0 (4.285)<br />

Equation 9 F A31z F B31z 436f S2 F D34z 0 (4.286)<br />

Taking moments about point D for the forces acting on Body 3 gives<br />

∑{M D3 } 1 {0} 1 (4.287)<br />

{R AD } 1 {F A31 } 1 {R BD } 1 {F B31 } 1 {R CD } 1 f S2 {R CI } 1 {0} 1<br />

(4.288)<br />

⎡ 0<br />

⎢<br />

15<br />

⎢<br />

⎣⎢<br />

239<br />

15 239⎤<br />

⎡F<br />

0 115<br />

⎥ ⎢<br />

⎥ ⎢<br />

F<br />

115 0 ⎦⎥<br />

⎣⎢<br />

F<br />

A31x<br />

A31y<br />

A31z<br />

⎤ ⎡ 0<br />

⎥<br />

<br />

⎢<br />

⎥<br />

1<br />

⎢<br />

⎦⎥<br />

⎣⎢<br />

239<br />

f<br />

S2<br />

1 239⎤<br />

⎡F<br />

0 115<br />

⎥ ⎢<br />

⎥ ⎢<br />

F<br />

115 0 ⎦⎥<br />

⎣⎢<br />

F<br />

B31x<br />

B31y<br />

B31z<br />

⎡ 0 23 98⎤<br />

⎡ 3 ⎤ ⎡0⎤<br />

⎢<br />

23 0 0<br />

⎥ ⎢<br />

9<br />

⎥<br />

<br />

⎢<br />

0<br />

⎥<br />

N mm<br />

⎢<br />

⎥ ⎢ ⎥ ⎢ ⎥<br />

⎣⎢<br />

98 0 0 ⎦⎥<br />

⎣⎢<br />

436⎦⎥<br />

⎣⎢<br />

0⎦⎥<br />

(4.289)<br />

⎤<br />

⎥<br />

⎥<br />

⎦⎥

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