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184 Multibody Systems Approach to Vehicle Dynamics<br />

The vertical forces acting on the front and rear tyres when the vehicle is at<br />

rest can be found by the simple application of static equilibrium. These<br />

forces, F SFz for the front wheel and F SRz for the rear wheel, are given by<br />

F<br />

(4.63a)<br />

It can be noted that the division of the loads by 2 in (4.63a) is simply to<br />

reflect that we are dealing with a symmetric case so that half of the mass is<br />

supported by the wheels on each side of the vehicle. In this analysis the<br />

vehicle will brake with a deceleration A x as shown in Figure 4.47. During<br />

braking weight transfer will arise, resulting in an increase in load on the<br />

front tyres by an additional load F B and a corresponding reduction in load<br />

F B on the rear tyres. This can be obtained by taking moments about either<br />

wheel, for mA x only and not mg, to give<br />

F<br />

SFz<br />

B<br />

mgb<br />

mga<br />

FSRz<br />

<br />

2L<br />

2L<br />

mAxh<br />

<br />

2L<br />

(4.64)<br />

Note that in determining the longitudinal braking forces F Fx and F Rx we<br />

have a case of indeterminancy with four unknown forces and only three<br />

equations of static equilibrium. The solution is found using another relationship<br />

to represent the relationship between the braking and vertical<br />

loads. At this stage we will assume that the braking system has been<br />

designed to proportion the braking effort so that the coefficient of friction<br />

is the same at the front and rear tyres. The generation of longitudinal<br />

braking force in the tyre is generally not this straightforward and will be<br />

covered in the next chapter. We can now combine the static and dynamic<br />

forces acting vertically on the wheels to give the full set of forces:<br />

mgb mAxh<br />

FFz FSFz FB<br />

<br />

2L<br />

2L<br />

mga mAxh<br />

FRz FRFz FB<br />

<br />

2L<br />

2L<br />

(4.65)<br />

(4.66)<br />

F Fx F Rx mA x (4.67)<br />

F<br />

F<br />

Fx<br />

Fz<br />

<br />

F<br />

F<br />

Rx<br />

Rz<br />

<br />

(4.68)<br />

4.8.2 Case study 2 – Static durability loadcase<br />

In order to demonstrate the application of road input loads to the suspension<br />

model a case study is presented here based on the same front suspension<br />

system described in section 4.7 for Case study 1. The loading to be<br />

applied is for the pothole braking case outlined in Table 4.8. Due to the<br />

severity of the loading, the suspension model used here is one that includes<br />

the full non-linear definition of all the bushes, the bump stop (spring aid) and<br />

a rebound stop. The model also includes a definition of the dampers and the<br />

damping terms in the bushes. These will be required later for an analysis

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