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Modelling and analysis of suspension systems 135<br />

Z 1<br />

GRF<br />

O 1<br />

X 1<br />

Y 1<br />

{R DG } 1<br />

D<br />

{F D } 1<br />

{R CG } 1<br />

G<br />

C<br />

{F B } 1<br />

{R AG } 1<br />

{R BG } 1<br />

m 2 {g} 1<br />

{F A } 1<br />

B<br />

A<br />

{F C } 1<br />

Fig. 4.4<br />

The wheel load reaction problem<br />

F Az F Bz F Cz F Dz m 2 g 0 (4.4)<br />

If we continue now to take moments about the mass centre G of Body 2 we<br />

have<br />

∑{M G } 1 {0} 1 (4.5)<br />

{R AG } {F A } 1 {R BG } 1 {F B } 1 {R CG } 1 {F C } 1<br />

{R DG } 1 {F D } 1 {0} 1 (4.6)<br />

If we expand the vector moment terms for the force acting at A only we get<br />

⎡ 0 AGz<br />

AGy<br />

⎤ ⎡ 0<br />

⎢<br />

⎥<br />

AG 0 AG<br />

⎢<br />

⎢ z<br />

x⎥<br />

⎢<br />

0<br />

⎢<br />

⎣<br />

AG AG 0 ⎥<br />

⎦ ⎣⎢<br />

F<br />

y x Az<br />

⎤ ⎡ AGyF<br />

⎥<br />

<br />

⎢<br />

⎥<br />

AGxF<br />

⎢<br />

⎦⎥<br />

⎣⎢<br />

0<br />

Az<br />

Az<br />

⎤<br />

⎥<br />

⎥<br />

⎦⎥<br />

(4.7)<br />

From (4.7) it is clear that we can now write equation (4.6) as<br />

AG y F Az BG y F Bz CG y F Cz DG y F Dz 0 (4.8)<br />

AG x F Az BG x F ABz CG x F Cz DG x F Dz 0 (4.9)<br />

It can now be seen that we have the classical case of an indeterminate problem<br />

where there are insufficient equations available to solve for the<br />

unknowns. The four unknowns here are F Az , F Bz , F Cz and F Dz . There are,<br />

however, only the three equations (4.4), (4.8) and (4.9) available to effect a<br />

solution. Trying to arrange the equations in matrix form for solution<br />

demonstrates the futility of the problem.

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