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Multibody systems simulation software 103<br />

02<br />

x<br />

z<br />

y<br />

I<br />

Action-only<br />

force<br />

x<br />

z<br />

y<br />

J<br />

03<br />

Fig. 3.24<br />

Action-only force<br />

02<br />

z<br />

x<br />

y<br />

I<br />

Torque acting<br />

on the I marker<br />

x<br />

Reaction torque acting<br />

on the J marker<br />

z<br />

y<br />

J<br />

03<br />

Fig. 3.25<br />

Action–reaction torque<br />

Rotational forces may be defined to be action–reaction or action-only. In<br />

either case the torque produced is assumed to act on the I marker. For an<br />

action-only torque it is again the z-axis of the J marker that is used, in this<br />

case to define the axis of rotation. If the torque is action–reaction the z-axes<br />

of the I and J marker must be parallel and point in the same direction as<br />

shown in Figure 3.25.<br />

Considering next the definition of translational spring elements we can<br />

start with a definition that is linear and introduce the use of system variables<br />

for the formulation of a force. As can be seen in Figure 3.26 the formulation<br />

of the spring force will be dependent on the length of the spring.<br />

This is made available through a system variable defined here as DM(I, J)<br />

which represents the scalar magnitude of the displacement between the I<br />

and the J marker at any point in time during the simulation. The spring<br />

force F S is initially defined here to be linear using<br />

F S k(DM(I, J) L) (3.45)<br />

where k is the spring stiffness and L is the free length of the spring, at zero<br />

force.<br />

The equation used in (3.45) to determine F S follows the required convention<br />

that the scalar value of force produced is positive when the spring is in compression,<br />

zero when it is at its free length and negative when it is in tension.

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